Json 字典中的百分比变化答案

【问题标题】：Percentage Change in Json DictionaryJson 字典中的百分比变化
【发布时间】：2018-05-31 19:08:14
【问题描述】：

我正在学习 python，我想了解如何分配升序和降序到2个不同的值变量。

在这种情况下，我将使用两个变量，其中一个获胜次数最多获胜率最低的另一个获得百分比变化：

api 列表内容如下：

[
  {
    "team_id": "FALCONS",
    "time_data": "2018-05-06T15:25:36.9524691Z",
    "wins": 11,
    "crow_size": 19563,
    "last_game": {
      "time_data": "2018-05-06T15:17:16.0000000Z",
      "data": "4e7a-bf0c-a97e5f32f58b",
      "take_side": "NA"
    }
  },
  {
    "team_id": "CARDINALS",
    "time_data": "2018-05-06T15:25:36.9212380Z",
    "wins": 14,
    "crow_size": 26000,
    "last_game": {
      "time_data": "2018-05-06T15:25:25.6850000Z",
      "data": "42ec-8326-445a22ea460f",
      "take_side": "NA"
    }
  },
  {
    "team_id": "BUFFALO",
    "time_data": "2018-05-06T15:25:36.7961978Z",
    "wins": 16,
    "crow_size": 34200,
    "last_game": {
      "time_data": "2018-05-06T15:07:50.0000000Z",
      "data": "44b7-86c1-6b969fccbe2e",
      "take_side": "NA"
    }
  },
  {
    "team_id": "COWBOYS",
    "time_data": "2018-05-06T15:25:36.9524691Z",
    "wins": 21,
    "crow_size": 15563,
    "last_game": {
      "time_data": "2018-05-06T15:17:16.0000000Z",
      "data": "4e7a-bf0c-a97e5f32f58b",
      "take_side": "NA"
    }
  },
  {
    "team_id": "DETROIT-LIONS",
    "time_data": "2018-05-06T15:25:36.9212380Z",
    "wins": 17,
    "crow_size": 23000,
    "last_game": {
      "time_data": "2018-05-06T15:25:25.6850000Z",
      "data": "42ec-8326-445a22ea460f",
      "take_side": "NA"
    }
  },
  {
    "team_id": "DOLPHINS",
    "time_data": "2018-05-06T15:25:36.7961978Z",
    "wins": 22,
    "crow_size": 24200,
    "last_game": {
      "time_data": "2018-05-06T15:07:50.0000000Z",
      "data": "44b7-86c1-6b969fccbe2e",
      "take_side": "NA"
    }
  }
]

这是一个非常大的列表，所以我只想要特定数量的团队不是全部，所以我可以做我的百分比变化数学

import requests
import json
import time
import datetime
import heapq
from pprint import pprint
from operator import itemgetter


url = 'api url'
data = requests.get(url)
data = json.loads(data.content)

data.sort(key=operator.itemgetter('wins'), reverse=True)


lookup = ["CARDINALS", "BUFFALO", "DOLPHINS", "COWBOYS"]



for item in data:
    teamname = item["team_id"]
    winstreak = item["wins"]
    for ex in lookup:
        if ex == teamname:
            print(teamname, winstreak)

到目前为止，我能做的只是打印出键和值用上面的公式，谁能帮我得到百分比变化从最高的胜利到最低的胜利？

【问题讨论】：

在任何团队词典中都没有 score 键。您是指与wins 键关联的值吗？
是的，得分意味着获胜，对此感到抱歉
对于问题中的示例值，“最高胜率与最低胜率的百分比变化”的输出是什么？
@JrDavid，我想为您最近提出的一个问题提出一个可能的答案，该问题使用 lomond 包被删除，您提出的“Json 字典中的 Python 循环”已被删除。不知道你为什么删除它，或者你可能已经让它工作了，但这是你的代码的一个可能的工作版本：repl.it/@downshift/CircularTomatoDecimal。不确定是否产生您想要的输出。只是想我会和你分享。

标签： python json python-3.x list dictionary

【解决方案1】：

根据您的团队范围，您可以使用min 和max：

import json
lookup = ["CARDINALS", "BUFFALO", "DOLPHINS", "COWBOYS"]
url = 'api url'
data = requests.get(url)
team_data = json.loads(data.content)
new_teams = [i for i in team_data if i['team_id'] in lookup]
min_win = min(new_teams, key=lambda x:x['wins'])['wins']
max_win = max(new_teams, key=lambda x:x['wins'])['wins']
change_win = (max_win-min_win)/float(min_win+max_win)

【讨论】：

【解决方案2】：

from __future__ import division # for python 2

hWin = None
for item in data:
    teamname = item["team_id"]
    winstreak = item["wins"]
    if teamname in lookup:
        if not hWin:
            hWin = winstreak
        percentChange = (hWin - winstreak) / hWin * 100
        print(teamname, winstreak,  '%i%%' % percentChange)

结果

('DOLPHINS', 22, '0%')
('COWBOYS', 21, '4%')
('BUFFALO', 16, '27%')
('CARDINALS', 14, '36%')

【讨论】：

【解决方案3】：

这样的事情可能会有所帮助：

lookup = ["CARDINALS", "BUFFALO", "DOLPHINS", "COWBOYS"]

wins = {}  # dictionary for team wins

for item in data:
    teamname = item["team_id"]
    winstreak = item["wins"]
    for ex in lookup:
        if ex == teamname:
            wins.update({teamname: winstreak}) # add team wins to dictionary
            print(teamname, winstreak)

low = min(wins.values())   # minimum of team wins
high = max(wins.values())  # maximum of team wins
print('low: {}, high: {}'.format(low, high))
print('percent difference: {}'.format(float(high-low)/low)) # print the percentage

输出：

CARDINALS 14
BUFFALO 16
COWBOYS 21
DOLPHINS 22
low: 14, high: 22
percent difference: 0.571428571429

【讨论】：