获取对象的 JSON 列表并将它们放入 python 列表中答案

【问题标题】：Taking JSON list of objects and putting them into a python list获取对象的 JSON 列表并将它们放入 python 列表中
【发布时间】：2018-11-23 15:37:39
【问题描述】：

我是在 Python 中使用 JSON 的新手。我有一个程序可以生成 10 个具有多个属性的字符（对象）。我正在使用 Python JSON 库将这些写入文件：

def saveCharsToFile(gameChars):
# Using a WITH operator for easy readability. creating and opening a file
# in write mode
with open("characterFile.json", "w") as write_file:
    # using the json.dump function to take the objects in the gameChars
    # list and serialise it into JSON
    json.dump([x.__dict__ for x in gameChars], write_file)
    # Tells the User that the file has been written

print("File 'characterFile.json' has been written to...")

以下是生成字符的其中一种类的示例：

# A subclass for creating a Wizard character, inherits the Character class
# and adds the power, sAttackPwr, and speed properties
class wizard(character):
    def __init__(self, CharPower, CharSAttackPwr, CharSpeed):
        # Getting the properties from the inheritted character Base Class
        character.__init__(self, "W", 100)
        self.power = CharPower
        self.sAttackPwr = CharSAttackPwr
        self.speed = CharSpeed


# Base Class for creating an RPG character
class character:
    # __init__ method, creates the name, type, health properties
    def __init__(self, charType, charHealth):
        self.name = rndName()
        self.type = charType
        self.health = charHealth

这是使用 saveCharsToFile 保存的文件的内容：

[{"name": "ing low fu ", "type": "B", "health": 100, "power": 60, "sAttackPwr": 10, "speed": 60}, {"name": "en ar da ", "type": "W", "health": 100, "power": 50, "sAttackPwr": 70, "speed": 30}, {"name": "ar fu fu ", "type": "B", "health": 100, "power": 70, "sAttackPwr": 20, "speed": 50}, {"name": "da low en ", "type": "W", "health": 100, "power": 50, "sAttackPwr": 70, "speed": 30}, {"name": "da fu cha ", "type": "D", "health": 100, "power": 90, "sAttackPwr": 40, "speed": 50}, {"name": "da ing el ", "type": "W", "health": 100, "power": 50, "sAttackPwr": 70, "speed": 30}, {"name": "cha kar low ", "type": "D", "health": 100, "power": 90, "sAttackPwr": 40, "speed": 50}, {"name": "ar da el ", "type": "D", "health": 100, "power": 90, "sAttackPwr": 40, "speed": 50}, {"name": "da da ant ", "type": "B", "health": 100, "power": 60, "sAttackPwr": 10, "speed": 60}, {"name": "el ing kar ", "type": "B", "health": 100, "power": 70, "sAttackPwr": 20, "speed": 50}]

我希望能够将其作为列表读回程序中，最好将它们实例化为具有上面该列表中字符属性值的对象。

这是我将文件读回程序的当前方式：

def openCharsToFile(gameChars):
    with open("characterFile.json") as read_file:
        y = json.load(read_file)
        for x in y:
            gameChars.insert[x, y]

        for z in gameChars:
            print(z.getStats())

但是当我运行这个程序时，我得到了以下错误：

Traceback (most recent call last):
    File "rpgProblemSolving.py", line 342, in <module>
        main()
    File "rpgProblemSolving.py",  line 338, in main
        openCharsToFile(gameChars)
    File "rpgProblemSolving.py", line 305, in openCharsToFile
        gameChars.insert[x, y]
TypeError: 'builtin_function_or_method' object is not subscriptable

如果有人有任何建议，将不胜感激，谢谢

【问题讨论】：

标签： python json python-3.x list object

【解决方案1】：

我相信您只想将您的角色添加到现有角色中，因此请改用 append。你的错误是你有[x, y]而不是(x, y)，但即使我们修复它也是没有意义的，因为插入的第一个参数（x）是列表的索引（gameChars），你的y将插入，这是没有意义的，因为x 是你的角色，y 是你的字典。

您打印字符print(z.getStats()) 的部分也不起作用，因为gameChars 仅包含字典形式的字符，当然没有getStats() 这样的方法。

def openCharsToFile(gameChars):
    with open("characterFile.json") as read_file:
        y = json.load(read_file)
        for x in y:
            gameChars.append(x)

        for z in gameChars:
            print(z.getStats())

【讨论】：