我必须在一行中每 3 个元素之后打印一个带有空格的网格，每三行之后打印一个空行，但我无法弄清楚代码

Question

我有一个 2D 列数组 = [[1, 1, 1, 1, 1, 1, 1, 1, 1], [2, 2, 2, 2, 2, 2, 2, 2, 2], [3, 3, 3, 3, 3, 3, 3, 3, 3], [4, 4, 4, 4, 4, 4, 4, 4, 4], [5, 5, 5, 5, 5, 5, 5, 5, 5], [6, 6, 6, 6, 6, 6, 6, 6, 6], [7, 7, 7, 7, 7, 7, 7, 7, 7], [8, 8, 8, 8, 8, 8, 8, 8, 8], [9, 9, 9, 9, 9, 9, 9, 9, 9]]，我必须像这样打印出来

enter image description here

    for n in range(9):
    for i in range(len(grid)):
        for j in range(len(grid)):
            print(grid[j][i] , ' ', end = '')

Answer 1

使用str.format 和enumerate 的一种方式：

fmt = "{}{}{} {}{}{} {}{}{}"
for n, g in enumerate(zip(*grid), 1):
    print(fmt.format(*g))
    if not n % 3:
        print("")

输出：

123 456 789
123 456 789
123 456 789

123 456 789
123 456 789
123 456 789

123 456 789
123 456 789
123 456 789

Answer 2

假设嵌套数组的长度都相同，您可以这样做：

from collections import defaultdict
result = defaultdict(str)
your_array = [[1, 1, 1, 1, 1, 1, 1, 1, 1], [2, 2, 2, 2, 2, 2, 2, 2, 2], [3, 3, 3, 3, 3, 3, 3, 3, 3], [4, 4, 4, 4, 4, 4, 4, 4, 4], [5, 5, 5, 5, 5, 5, 5, 5, 5], [6, 6, 6, 6, 6, 6, 6, 6, 6], [7, 7, 7, 7, 7, 7, 7, 7, 7], [8, 8, 8, 8, 8, 8, 8, 8, 8], [9, 9, 9, 9, 9, 9, 9, 9, 9]]

for n in range(len(your_array[0])):
  for i in range(len(your_array)):
   result[n] += ' ' if i%3 == 0 else ''
   result[n] += str(your_array[i][n])

for line, j in result.items():
  if line % 3 == 0:
    print('')
  print(j)

输出：

 123 456 789
 123 456 789
 123 456 789

 123 456 789
 123 456 789
 123 456 789

 123 456 789
 123 456 789
 123 456 789

评论更新

defaultdict 在这里只是一个便利类，所以它是完全可选的。没有 defaultdict 的相同代码如下所示：

result = {}
your_array = [[1, 1, 1, 1, 1, 1, 1, 1, 1], [2, 2, 2, 2, 2, 2, 2, 2, 2], [3, 3, 3, 3, 3, 3, 3, 3, 3], [4, 4, 4, 4, 4, 4, 4, 4, 4], [5, 5, 5, 5, 5, 5, 5, 5, 5], [6, 6, 6, 6, 6, 6, 6, 6, 6], [7, 7, 7, 7, 7, 7, 7, 7, 7], [8, 8, 8, 8, 8, 8, 8, 8, 8], [9, 9, 9, 9, 9, 9, 9, 9, 9]]

for n in range(len(your_array[0])):
  for i in range(len(your_array)):
   if n not in result:
     result[n] = ''
   result[n] += ' ' if i%3 == 0 else ''
   result[n] += str(your_array[i][n])

for line, j in result.items():
  if line % 3 == 0:
    print('')
  print(j)

此外，如果您想按照下面的建议使用 zip，您的代码将简化为：

your_array = [[1, 1, 1, 1, 1, 1, 1, 1, 1], [2, 2, 2, 2, 2, 2, 2, 2, 2], [3, 3, 3, 3, 3, 3, 3, 3, 3], [4, 4, 4, 4, 4, 4, 4, 4, 4], [5, 5, 5, 5, 5, 5, 5, 5, 5], [6, 6, 6, 6, 6, 6, 6, 6, 6], [7, 7, 7, 7, 7, 7, 7, 7, 7], [8, 8, 8, 8, 8, 8, 8, 8, 8], [9, 9, 9, 9, 9, 9, 9, 9, 9]]

your_array = zip(*your_array)
for idx, sub_array in enumerate(your_array):
  result_str = ''
  for sub_idx, value in enumerate(sub_array):
   result_str += ' ' if sub_idx%3 == 0 else ''
   result_str += str(value)
  if idx % 3 == 0:
    print('')
  print(result_str)