【发布时间】:2020-08-27 01:44:32
【问题描述】:
我在list1 中有 4 个df:
df1df2df3df4
list1 中的每个数据帧都进入一个 for 循环并提供单个输出,但在打印输出之前,我希望给出一个标题,以便我能够识别输出属于哪个组。即它是属于高、低、中还是平均
list2 具有需要为 4 个输出提供的所有标题。
list2 = ["High","Medium","Low","Average"]
例子:
Before df1 output is printed i wanted the heading to be 'High'
Before df2 output is printed i wanted the heading to be 'Medium'
Before df3 output is printed i want the heading to be printed as 'Low'
Before df4 output is printed i want the heading to be printed as 'Average'
下面是我的代码:
import os
os.chdir(r'C:\Users\91979\Downloads\head code\src')
from classStruct.model import model
list1 = [df1,df2,df3,df4]
list2 = ["High","Medium","Low", "Average"]
for i in list1:
needed_cols = i.columns
target_col = ['Rejection (%)']
cols = list(set(needed_cols) - set(target_col))
totData = i
totData = totData.round(decimals=2)
Model1 = model(totData,cols,['Rejection (%)'])
clustSet = pd.DataFrame([C.clusterCenter for C in Model1.clustersList])
Model1.predictor(clustSet, ["Rejection (%)"], Normalize=False)
Model1.optimalClusterRejectionSeries = round(min(clustSet['Rejection (%)Predicted']),4)
col_list = ['GCS (kg/cm2)', 'Inert Fines (%)', 'Volatile Matter (%)',
'LOI (%)', 'Active Clay (%)', 'GFN/AFS (no)', 'Compactability (%)',
'Wet Tensile Strength (gm/cm2)', 'Moisture (%)',
'Permeability (no)', 'Temp. of Sand after mix.(C)']
Model1.deNormalizeColumns(col_list, clustSet).to_csv("Predicted_optimal.csv")
Model1.deNormalizeColumns(col_list, clustSet)
for j in list2:
print(j)
print(pd.DataFrame(clustSet[clustSet['Rejection (%)Predicted'] == clustSet['Rejection (%)Predicted'].min()]))
print('\n')
print('\n')
我应该在代码的哪一部分打印list2 中的标题,以便获得正确的 4 次迭代和正确的标题。
【问题讨论】:
标签: python python-3.x pandas python-2.7