使用 re python 解析 json 值答案

【问题标题】：parse json value with re python使用 re python 解析 json 值
【发布时间】：2021-02-01 23:11:17
【问题描述】：

我有这个键：json 中的值

"text": "CRITICAL: Alert for device amst-asw1 - Port status Down\nSeverity: critical\nTimestamp: 2021-02-01 10:53:16\nUnique-ID: 307849\nRule:  Port status Down  Faults:\n  #1: sysObjectID = .1.3.6.1.4.1.2636.1.1.1.2.63; sysDescr = Juniper Networks, Inc. ex4300-32f Ethernet Switch, kernel JUNOS 17.3R3-S4.2, Build date: 2019-04-10 20:40:30 UTC Copyright (c) 1996-2019 Juniper Networks, Inc.; location_id = 17; port_id = 4101; ifDescr = vme; \n  #2: sysObjectID = .1.3.6.1.4.1.2636.1.1.1.2.63; sysDescr = Juniper Networks, Inc. ex4300-32f Ethernet Switch, kernel JUNOS 17.3R3-S4.2, Build date: 2019-04-10 20:40:30 UTC Copyright (c) 1996-2019 Juniper Networks, Inc.; location_id = 17; port_id = 4128; ifDescr = ge-0/0/4; \n  #3: sysObjectID = .1.3.6.1.4.1.2636.1.1.1.2.63; sysDescr = Juniper Networks, Inc. ex4300-32f Ethernet Switch, kernel JUNOS 17.3R3-S4.2, Build date: 2019-04-10 20:40:30 UTC Copyright (c) 1996-2019 Juniper Networks, Inc.; location_id = 17; port_id = 4136; ifDescr = ge-0/0/8; \nAlert sent to:\n",

我只想解析该值并从中获取 ifDescr 字符串。

import json
import os
import requests
import re
with open('alerts.json', 'r') as json_file:
 data = json.load(json_file)
    for a in data['history']:
            text = a.get('text')
            if re.search(r"ifDescr", text):
             print(text)

我明白了

CLEARED: Device amst-asw1 recovered from Port status Down
Severity: critical
 Time elapsed: 3d 20h 25m 34s Timestamp: 2021-02-01 10:41:39
Unique-ID: 307845
Rule:  Port status Down  Faults:
  #1: sysObjectID =&gt; .1.3.6.1.4.1.2636.1.1.1.2.63; sysDescr =&gt; Juniper Networks, Inc. ex4300-32f Ethernet Switch, kernel JUNOS 17.3R3-S4.2, Build date: 2019-04-10 20:40:30 UTC Copyright (c) 1996-2019 Juniper Networks, Inc.; location_id =&gt; 17; port_id =&gt; 4101; ifDescr =&gt; vme; 
  #2: sysObjectID =&gt; .1.3.6.1.4.1.2636.1.1.1.2.63; sysDescr =&gt; Juniper Networks, Inc. ex4300-32f Ethernet Switch, kernel JUNOS 17.3R3-S4.2, Build date: 2019-04-10 20:40:30 UTC Copyright (c) 1996-2019 Juniper Networks, Inc.; location_id =&gt; 17; port_id =&gt; 4128; ifDescr =&gt; ge-0/0/4; 
  #3: sysObjectID =&gt; .1.3.6.1.4.1.2636.1.1.1.2.63; sysDescr =&gt; Juniper Networks, Inc. ex4300-32f Ethernet Switch, kernel JUNOS 17.3R3-S4.2, Build date: 2019-04-10 20:40:30 UTC Copyright (c) 1996-2019 Juniper Networks, Inc.; location_id =&gt; 17; port_id =&gt; 4136; ifDescr =&gt; ge-0/0/8; 
Alert sent to:

我只想要这个

ifDescr = ge-0/0/8

【问题讨论】：

标签： json python-3.x python-re

【解决方案1】：

你应该使用正则表达式：

m = re.search('ifDescr\s*=\s*(.*)\s*;', text)
if m:
    ifDescr = m.group(1)

正则表达式解释：

ifDescr ：按字面意思搜索“ifDescr”
\s* : 任意数字或空格字符
= : '=' char 字面意思
(.*) ：你要匹配的组（.* 任意数量的任意字符）
\s*; : 任何数字或空格字符后跟 ';'字符字面意思

【讨论】：