jquery select 2 选项未格式化答案

【问题标题】：jquery select 2 options not getting formattedjquery select 2 选项未格式化
【发布时间】：2017-08-17 13:03:46
【问题描述】：

我有这种格式的结果，无法加载选项：你能帮帮我吗：结果方法应该是什么样子？

          [{"id":2,"name":512843},{"id":2,"name":512844},
           {"id":2,"name":512847},{"id":2,"name":512874},
           {"id":2,"name":512875},{"id":2,"name":512880},
           {"id":2,"name":512884},{"id":2,"name":512886},
           {"id":2,"name":512887},{"id":2,"name":512888},
           {"id":2,"name":512892},{"id":2,"name":512896},
           {"id":2,"name":512907},{"id":2,"name":512910},
           {"id":2,"name":512911},{"id":2,"name":512913},
           {"id":2,"name":512914},{"id":2,"name":512917},
           {"id":2,"name":512925},{"id":2,"name":512930},
           {"id":2,"name":512931},{"id":2,"name":512935}]

它只是说加载失败

        processResults: function (data) {
            return {
                results: $.map(data.items, function (item) {
                    return {
                        text: item.name,
                        id: item.id
                    }
                })
            };
        }

【问题讨论】：

标签： jquery ajax jquery-ui select2

【解决方案1】：

我可以找到答案，我们应该将 json 输出为

results = [{"id":2,"name":512847},{"id":2,"name":512874},
           {"id":2,"name":512875},{"id":2,"name":512880},
           {"id":2,"name":512884},{"id":2,"name":512886},
           {"id":2,"name":512887},{"id":2,"name":512888},
           {"id":2,"name":512892},{"id":2,"name":512896},
           {"id":2,"name":512907},{"id":2,"name":512910},
           {"id":2,"name":512911},{"id":2,"name":512913},
           {"id":2,"name":512914},{"id":2,"name":512917},
           {"id":2,"name":512925},{"id":2,"name":512930},
           {"id":2,"name":512931},{"id":2,"name":512935}]

当我拥有它时，一切都准备就绪，select2 开始工作了！

【讨论】：

我看不出有什么不同——看起来一样