【问题标题】:Detect if python script is run from an ipython shell, or run from the command line检测 python 脚本是从 ipython shell 运行,还是从命令行运行
【发布时间】:2014-05-27 07:24:04
【问题描述】:

有什么方法可以检测 python 脚本是从 python 或 ipython shell 运行,还是从命令行运行,例如使用python scrip.py

我想用它来设置我的 matplotlib 环境并根据脚本的运行方式保存或显示图形。当我从命令行运行绘图脚本时,我希望脚本使用非标准的 matplotlib 后端并将图形保存到带有plt.savefig() 的文件中,但如果我使用@从 ipython shell 内部运行它987654323@,我想用plt.show()显示图形。

类似这样的:

import matplotlib
if run_from_command_line:
    matplotlib.use("non-standard-backend")

import matplotlib.pyplot as plt
if run_from_interactive_shell:
    plt.ion() // Turn on interactive mode in matplotlib

// Do plotting

if run_from_command_line:
    plt.savefig(filename)
else:
    plt.show()

【问题讨论】:

    标签: python matplotlib ipython


    【解决方案1】:

    方法一

    在 IPython 中运行时,有一个名为 __IPYTHON__ 的全局变量集。您可以通过以下方式检查是否存在:

    try:
        __IPYTHON__
    except NameError:
        print "Not in IPython"
    else:
        print "In IPython"
    

    方法 2

    正如thread 指出的那样,您还可以在脚本中查找get_ipython 函数,不仅可以检查您是否从 IPython 运行,还可以检查 IPython 的配置。

    方法 3

    您还可以使用inspect 模块来检查堆栈并确定您是否正在从交互式解释器等运行。

    所以一个示例文件:

    # test.py
    import inspect
    
    for frame in inspect.stack():
        print frame
    

    使用python test.py 从命令行运行时,输出为:

    (<frame object at 0x100378530>, 'test.py', 3, '<module>', ['for frame in inspect.stack():\n'], 0)
    

    execfile来自交互式解释器时:

    >>> execfile( "test.py" )
    (<frame object at 0x1003795e0>, 'test.py', 3, '<module>', ['for frame in inspect.stack():\n'], 0)
    (<frame object at 0x100379430>, '<stdin>', 1, '<module>', None, None)
    

    在 IPython 中运行时:

    In [1]: %run test
    (<frame object at 0x1029002a0>, '/Users/ebarr/Scripts/SO/test.py', 3, '<module>', ['for frame in inspect.stack():\n'], 0)
    (<frame object at 0x102900020>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/utils/py3compat.py', 224, 'execfile', ['            builtin_mod.execfile(filename, *where)\n'], 0)
    (<frame object at 0x101d78e20>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/core/interactiveshell.py', 2537, 'safe_execfile', ['                py3compat.execfile(fname,*where)\n'], 0)
    (<frame object at 0x101d78c30>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/core/magics/execution.py', 703, 'run', ['                                       exit_ignore=exit_ignore)\n'], 0)
    (<frame object at 0x101d76390>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/core/magics/execution.py', 717, 'run', ['                            run()\n'], 0)
    (<frame object at 0x101d61760>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/core/magic.py', 193, '<lambda>', ['        call = lambda f, *a, **k: f(*a, **k)\n'], 0)
    (<frame object at 0x101d761a0>, '<string>', 2, 'run', None, None)
    (<frame object at 0x101d603e0>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/core/interactiveshell.py', 2126, 'run_line_magic', ['                result = fn(*args,**kwargs)\n'], 0)
    (<frame object at 0x101d5f1f0>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/core/interactiveshell.py', 2205, 'magic', ['        return self.run_line_magic(magic_name, magic_arg_s)\n'], 0)
    (<frame object at 0x101d75e40>, '<ipython-input-1-59a1e9768ae2>', 1, '<module>', [u"get_ipython().magic(u'run test')\n"], 0)
    (<frame object at 0x101d75990>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/core/interactiveshell.py', 2883, 'run_code', ['                exec(code_obj, self.user_global_ns, self.user_ns)\n'], 0)
    (<frame object at 0x101d75760>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/core/interactiveshell.py', 2833, 'run_ast_nodes', ['                if self.run_code(code):\n'], 0)
    (<frame object at 0x101d71950>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/core/interactiveshell.py', 2741, 'run_cell', ['                                   interactivity=interactivity, compiler=compiler)\n'], 0)
    (<frame object at 0x101d6ce10>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/terminal/interactiveshell.py', 567, 'interact', ['                    self.run_cell(source_raw, store_history=True)\n'], 0)
    (<frame object at 0x101d6c870>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/terminal/interactiveshell.py', 443, 'mainloop', ['                    self.interact(display_banner=display_banner)\n'], 0)
    (<frame object at 0x101716d60>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/terminal/ipapp.py', 371, 'start', ['            self.shell.mainloop()\n'], 0)
    (<frame object at 0x1017006f0>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/config/application.py', 563, 'launch_instance', ['        app.start()\n'], 0)
    (<frame object at 0x1014fbdd0>, '/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/__init__.py', 118, 'start_ipython', ['    return launch_new_instance(argv=argv, **kwargs)\n'], 0)
    (<frame object at 0x100378560>, '/Library/Frameworks/Python.framework/Versions/2.7/bin/ipython', 11, '<module>', ['    sys.exit(start_ipython())\n'], 0)
    

    【讨论】:

    • FYI:__IPYTHON__ 变量在使用ipython scrip.py 从命令行运行脚本或使用In []: run scrip.py 在 ipython shell 中运行时都设置,get_ipython() 返回相同的东西(除了最后的内存地址)在这两种情况下。但是inspec 模块似乎可以解决问题。