如何在 sqlite 查询中使用 mssql 查询中的值答案

【问题标题】：how to use value from a mssql query in a sqlite query如何在 sqlite 查询中使用 mssql 查询中的值
【发布时间】：2016-04-18 13:10:53
【问题描述】：

我有两张表，一张在 ms sql 中，另一张在 sqlite3 中我需要将 mssql 表中的一个字段更新为 sqlite3 表中的相关值。

这是我的代码：

import pypyodbc
import sqlite3

connection = pypyodbc.connect('Driver={SQL Server};'
                              'Server=****'
                              'Database=****;'
                              'uid=****;pwd=****')

cursor = connection.cursor()
SQLCommand = ("select ObjectId, ObjectColumnName,Label from LocalizedLabel "
              "where LanguageId = 1065")

sqlUpdate = ("UPDATE LocalizedLabel "
             "SET Label = ? "
             "WHERE ObjectId = ? and ObjectColumnName = ? and LanguageId = 1065")

cursor.execute(SQLCommand)
results = cursor.fetchall()

srcDB = sqlite3.connect('crmLLDB')

for result in results:
    val = (result[0], result[1])
    print('SELECT "1065" FROM crm '
          'WHERE UPPER(ObjectID)= UPPER(%s) AND ObjectColumnName = %s' % val)
    srcCursor = srcDB.execute('SELECT "1065" FROM crm '
                              'WHERE UPPER(ObjectID)= UPPER(?) AND ObjectColumnName = ?', val)
    if srcCursor.fetchone() is None:
        print("No translation found for " + result[2])
    else:
        translation = srcCursor.fetchone()[0]
        updateVals = (translation, result[0], result[1])
        cursor.execute(sqlUpdate, updateVals)


connection.close()
srcDB.close()

objectId 是一个GuID，其他字段都是字符串

打印函数返回：

SELECT "1065" FROM crm WHERE UPPER(ObjectID)= UPPER(b'0340B506-2341-DB11-898A-0007E9E17EBD') AND ObjectColumnName = DisplayName

当观察者给出：

result[0] = 'b\\'0340B506-2341-DB11-898A-0007E9E17EBD\\''
result[1] = 'DisplayName'

这个查询当然会返回这个错误：

[1] [SQLITE_ERROR] SQL error or missing database (near "'0340B506-2341-DB11-898A-0007E9E17EBD'": syntax error)

这个查询：

SELECT "1065" FROM crm WHERE UPPER(ObjectID)= UPPER('0340B506-2341-DB11-898A-0007E9E17EBD') AND ObjectColumnName = 'DisplayName'

返回完美答案，有人可以指出我的问题吗？

【问题讨论】：

标签： python-3.x sqlite pypyodbc

【解决方案1】：

显然问题出在pypyodbc 和GuId 上，我使用了pyodbc，现在一切正常！

我的最终代码，如果将来有 googler 路过：

import pyodbc
import sqlite3

startTme = datetime.now()
connection = pyodbc.connect('Driver={SQL Server};'
                            'Server=*****;'
                            'Database=****;'
                            'uid=sa;pwd=*****')

cursor = connection.cursor()
SQLCommand = ("select ObjectId, ObjectColumnName,Label from LocalizedLabel "
              "where LanguageId = 1065")

sqlUpdate_p = ("UPDATE LocalizedLabel "
               "SET Label = ? "
               "WHERE ObjectId = ? and ObjectColumnName = ? and LanguageId = 1065")

cursor.execute(SQLCommand)
results = cursor.fetchall()

srcDB = sqlite3.connect('crmLLDB')

jobLength = str(len(results))
i = 0

for result in results:
    val = (result[0], result[1])
    srcCursor = srcDB.execute('SELECT "1065" FROM crm '
                              'WHERE UPPER(ObjectID)= UPPER(?) AND ObjectColumnName = ?', val)
    trans = srcCursor.fetchall()
    for tr in trans:
        updateVals = (tr[0], result[0], result[1])
        cursor.execute(sqlUpdate_p, updateVals)
        i += 1

connection.commit()
connection.close()
srcDB.close()

【讨论】：