选择按钮的 Xpath

Question

我拥有的以下检查代码是单击我可以确认订单的按钮

<button type="submit" class="button btn btn-default button-medium">
                <span>I confirm my order<i class="icon-chevron-right right"></i></span>
</button>
<span>I confirm my order<i class="icon-chevron-right right"></i></span>

我试过的那个：

driver.findElement(By.xpath("//button[contains(text(),'I confirm my order')]\"")).click();

使用 Eclipse 作为 Selenium 测试的 IDE 时出现以下错误：

org.openqa.selenium.InvalidSelectorException: invalid selector: Unable to locate an element with the xpath expression //button[contains(text(),'I confirm my order')]" because of the following error:
SyntaxError: Failed to execute 'evaluate' on 'Document': The string '//button[contains(text(),'I confirm my order')]"' is not a valid XPath expression.

Answer 1

试试这个：

driver.find_element_by_xpath('//button[@type="submit"]/span[1]').click()

Answer 2

文本我确认我的订单位于<button> 元素的子<span> 内。因此，对于元素上的click()，您可以使用以下任一Locator Strategies：

• cssSelector:

  driver.findElement(By.cssSelector("button.button.btn.btn-default.button-medium > span i.icon-chevron-right.right")).click();
  

• xpath:

  driver.findElement(By.xpath("//button[@class='button btn btn-default button-medium'][./span[contains(., 'I confirm my order')]]")).click();
  

但是，由于该元素是启用了JavaScript 的元素，因此要在该元素上使用click()，您需要为elementToBeClickable() 诱导WebDriverWait，并且您可以使用以下任一Locator Strategies：

• cssSelector:

  new WebDriverWait(driver, 20).until(ExpectedConditions.elementToBeClickable(By.cssSelector("button.button.btn.btn-default.button-medium > span i.icon-chevron-right.right"))).click();
  

• xpath:

  new WebDriverWait(driver, 20).until(ExpectedConditions.elementToBeClickable(By.xpath("//button[@class='button btn btn-default button-medium'][./span[contains(., 'I confirm my order')]]"))).click();