【发布时间】:2020-07-15 14:41:43
【问题描述】:
我有一个从带有tabula-py 的 PDF 中提取的 Pandas DataFrame。
PDF是这样的:
+--------------+--------+-------+
| name | letter | value |
+--------------+--------+-------+
| A short name | a | 1 |
+-------------------------------+
| Another | b | 2 |
+-------------------------------+
| A very large | c | 3 |
| name | | |
+-------------------------------+
| other one | d | 4 |
+-------------------------------+
| My name is | e | 5 |
| big | | |
+--------------+--------+-------+
如您所见,A very large name 有一个换行符,并且由于原始 pdf 没有边框,因此在 DataFrame 中创建了一行 ['name', NaN, NaN] 和另一行 ['A very large', 'c', 3],当我只想要一个时内容:['A very large name', 'c', 3]。
My name is big 也是如此
当这行中的其余单元格为NaN 时,我试图将name 单元格的内容与前一个单元格连接起来。然后删除 NaN 行。
但任何其他获得相同结果的策略都是受欢迎的。
import pandas as pd
import numpy as np
data = {
"name": ["A short name", "Another", "A very large", "name", "other one", "My name is", "big"],
"letter": ["a", "b", "c", np.NaN, "d", "e", np.NaN],
"value": [1, 2, 3, np.NaN, 4, 5, np.NaN],
}
df = pd.DataFrame(data)
data_expected = {
"name": ["A short name", "Another", "A very large name", "other one", "My name is big"],
"letter": ["a", "b", "c", "d", "e"],
"value": [1, 2, 3, 4, 5],
}
df_expected = pd.DataFrame(data_expected)
我正在尝试这样的代码,但无法正常工作
# Not works and not very `pandastonic`
nan_indexes = df[df.iloc[:, 1:].isna().all(axis='columns')].index
df.loc[nan_indexes - 1, "name"] = df.loc[nan_indexes - 1, "name"].str.cat(df.loc[nan_indexes, "name"], ' ')
# remove NaN rows
【问题讨论】: