【发布时间】:2018-06-25 03:19:49
【问题描述】:
我有一个订单表 (orders)、一个状态表 (order_statuses) 和一个用作状态日志的数据透视表 (order_order_status)。
当订单状态发生变化时,会在数据透视表中添加一个条目。该订单的数据透视表中的最新条目将是它的当前状态。
我需要能够显示当前具有给定状态的所有订单。例如,所有处于“报价”状态的订单。有没有一种雄辩的方式来构建这个查询?
(编辑,附加说明:订单的当前状态是状态日志中具有最新“created_at”日期的条目。)
以下是模式的一些示例:
mysql> SELECT * FROM orders WHERE id = 2;
+----+---------+--------------+---------------+----------------------+---------------------+---------------------+
| id | user_id | order_number | job_reference | accounting_reference | created_at | updated_at |
+----+---------+--------------+---------------+----------------------+---------------------+---------------------+
| 2 | 73 | 37-5 | Janis Joplin | NULL | 2018-06-25 02:27:21 | 2018-06-25 02:27:21 |
+----+---------+--------------+---------------+----------------------+---------------------+---------------------+
mysql> SELECT * FROM order_order_status WHERE order_id = 2 ORDER BY created_at;
+------+----------+-----------------+---------+---------------------+---------------------+
| id | order_id | order_status_id | user_id | created_at | updated_at |
+------+----------+-----------------+---------+---------------------+---------------------+
| 2 | 2 | 2 | 753 | 2012-06-27 09:47:00 | 2012-06-27 09:47:00 |
| 3 | 2 | 3 | 753 | 2012-06-27 09:56:00 | 2012-06-27 09:56:00 |
| 4 | 2 | 4 | 753 | 2012-06-27 09:56:00 | 2012-06-27 09:56:00 |
| 5 | 2 | 5 | 1153 | 2012-06-27 10:13:00 | 2012-06-27 10:13:00 |
| 6 | 2 | 6 | 1153 | 2012-06-27 10:13:00 | 2012-06-27 10:13:00 |
| 7 | 2 | 10 | 1153 | 2012-06-27 10:13:00 | 2012-06-27 10:13:00 |
| 8 | 2 | 7 | 1153 | 2012-06-27 10:13:00 | 2012-06-27 10:13:00 |
| 9 | 2 | 10 | 1153 | 2012-06-27 10:42:00 | 2012-06-27 10:42:00 |
| 10 | 2 | 7 | 1153 | 2012-06-27 10:42:00 | 2012-06-27 10:42:00 |
| 11 | 2 | 8 | 753 | 2012-06-27 10:44:00 | 2012-06-27 10:44:00 |
| 12 | 2 | 9 | 753 | 2012-06-27 10:45:00 | 2012-06-27 10:45:00 |
| 2222 | 2 | 10 | 54 | 2013-01-03 12:08:00 | 2013-01-03 12:08:00 |
+------+----------+-----------------+---------+---------------------+---------------------+
mysql> SELECT * FROM order_statuses;
+----+----------------+----------------+---------------------+---------------------+
| id | title | tag | created_at | updated_at |
+----+----------------+----------------+---------------------+---------------------+
| 1 | Archived Quote | archived_quote | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
| 2 | Quote | quote | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
| 3 | Order | order | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
| 4 | Confirmed | confirmed | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
| 5 | Manufacturing | manufacturing | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
| 6 | Painting | painting | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
| 7 | Dispatched | dispatched | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
| 8 | Invoiced | invoiced | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
| 9 | Paid | paid | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
| 10 | Closed | closed | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
| 11 | Archived | archived | 2018-06-25 02:25:28 | 2018-06-25 02:25:28 |
+----+----------------+----------------+---------------------+---------------------+
编辑:进一步澄清。这是返回所需结果的 SQL 查询。我正在寻找一种获得相同结果的雄辩方法:
SELECT a.order_status_id, c.*
FROM order_order_status a
INNER JOIN (
SELECT order_id, MAX(updated_at) last_date
FROM order_order_status
GROUP BY order_id
) b ON a.order_id = b.order_id AND a.updated_at = b.last_date
INNER JOIN
orders c
ON c.id = a.order_id
WHERE a.order_status_id = (SELECT id from order_statuses where tag="closed")
【问题讨论】:
标签: php mysql laravel eloquent pivot-table