PHP：如何比较嵌套关联数组中的值？

Question

我正在努力思考如何做到这一点……

我有一个类似的东西：

$contributors = array(
[0] => array(
    [name] => 'John',
    [role] => 'author',
    ),
[1] => array(
    [name] => 'Gail',
    [role] => 'author',
    ),
[2] => array(
    [name] => 'Beth',
    [role] => 'illustrator',
    ),
)

我正在尝试使用这些信息来构建详细的署名，例如：

由约翰和盖尔撰写。由贝丝设计。

我需要将每个 role 与上一个和下一个进行比较，以便：

1. 在每个role 的第一个实例之前使用标签
2. 用逗号分隔同一role 的多个实例
3. 在每个role 的最后一个实例之前使用“and”而不是逗号

我不是 PHP 专家，所以我很难弄清楚如何解决这个问题！我有一个函数可以根据role 输出正确的标签，但这是我似乎无法弄清楚的比较。我考虑过foreach 和while 循环，但似乎都不能胜任这项工作。我从未使用过for 循环，所以我不知道它是否适用。

一些额外的背景：

• 我正在使用 WordPress 和高级自定义字段插件。
• $contributors 是 ACF Repeater 字段的值，其中 name 和 role 是子字段。 （我已经简化了名称以使事情变得更容易。）

Answer 1

您可以按角色对数组进行分组，并使用array_pop 删除元素。 implode 剩余的数组元素，只需附加 弹出值。

$contributors = array(
    array(
        "name" => 'John',
        "role" => 'author',
        ),
    array(
        "name" => 'Gail',
        "role" => 'author',
        ),
    array(
        "name" => 'Jose',
        "role" => 'author',
        ),
    array(
        "name" => 'Thomas',
        "role" => 'author',
        ),
    array(
        "name" => 'Beth',
        "role" => 'illustrator',
        ),
    array(
        "name" => 'Mary',
        "role" => 'producer',
        ),
    array(
        "name" => 'Criss',
        "role" => 'producer',
        ),
);

//Grouped the names according to role
$grouped = array_reduce($contributors, function($c, $v) {
    if ( !isset( $c[ $v['role'] ] ) ) $c[ $v['role'] ] = array();
    $c[ $v['role'] ][] = $v['name'];
    return $c;
}, array());


//Construct final Array
$final = array();
foreach( $grouped as $key => $group ) {
    $last = array_pop( $group );

    if ( count( $group ) == 0 ) $final[ $key ] = $last; /* One one name on the role, no need to do anything*/
    else $final[ $key ] = implode( ", ", $group ) . " and " . $last;
}

echo "<pre>";
print_r( $final );
echo "</pre>";

这将导致：

Array
(
    [author] => John, Gail, Jose and Thomas
    [illustrator] => Beth
    [producer] => Mary and Criss
)

您现在可以将其用作

echo 'Written by ' . $final["author"] . '. Designed by ' . $final["illustrator"] . '. Produced by ' . $final["producer"];

结果是：

由约翰、盖尔、何塞和托马斯撰写。由贝丝设计。由。。。生产 玛丽和克里斯

Answer 2

你可以这样尝试-

$contributors = array(
  array(
    'name' => 'John',
    'role' => 'author',
  ),
  array(
    'name' => 'Gail',
    'role' => 'author',
  ),
  array(
    'name' => 'Ali',
    'role' => 'author',
  ),
  array(
    'name' => 'Beth',
    'role' => 'illustrator',
  )
);

#This function prepare array to expected String
function PrepareArray($data){
  $combined = '';
  if (count($data)>1) {
    $last       = array_slice($data, -1);
    $first      = join(', ', array_slice($data, 0, -1));
    $both       = array_filter(array_merge(array($first), $last), 'strlen');
    $combined   = join(' and ', $both);
  }else{
    $combined = implode('', $data);
  }
  return $combined;
}

$authors    = array();
$designers  = array();

foreach ($contributors as $key => $value) {
  if ($value['role']=='author') {
    $authors[]      = $value['name'];        #Keep Authors name in Array
  }else if ($value['role']=='illustrator') {
    $designers[]    = $value['name'];            #Keep Designers name in Array
  }
}

$authors    = PrepareArray($authors);
$designers  = PrepareArray($designers);

echo "Written by {$authors}. Designed by {$designers}.";

输出：

由约翰、盖尔和阿里撰写。由贝丝设计。

Answer 3

试试下面的代码：

<?php

$contributors = array(
  0 => array(
    'name' => 'John',
    'role' => 'author',
  ),
  1 => array(
    'name' => 'Gail',
    'role' => 'author',
  ),
  2 => array(
    'name' => 'Beth',
    'role' => 'illustrator',
 ),
 3 => array(
    'name' => 'Albert',
    'role' => 'author',
 ),
);


$labels = ['author'=>'Written by', 'illustrator'=>'Designed by', 'producer'=>'Produced by'];

$new_contributors = [];

foreach($contributors as $cont){
    $new_contributors[$cont['role']][] = $cont['name'];
}
$str = '';
foreach($labels as $role=>$label){
  if(isset($new_contributors[$role]) && is_array($new_contributors[$role])){
    $str .= ' '.$label.' ';
    foreach($new_contributors[$role] as $key=>$new_contributor){
        $count = count($new_contributors[$role]);
        if(($count - $key) == 1 ){
            $str .= ' and ';
            $str .= $new_contributor;
        }else if(($count - $key) == 2){
            $str .= $new_contributor;
        }else{
            $str .= $new_contributor.', ';
        }
    }
  }

}

echo $str;