php比较关键字的字符串答案

【问题标题】：php compare string of keywordsphp比较关键字的字符串
【发布时间】：2011-07-12 12:17:27
【问题描述】：

我需要将这两个关键字字符串与php进行比较。

$original_keywords = cat, dog, mouse

$possible_keywords_1 = "cat, dog, hamster";       
$possible_keywords_2 = "cat, sheep, goat";

我需要一个 php 脚本来将数值“1”分配给第一个可能的字符串（1 个匹配项），将“2”分配给第二个可能的字符串（2 个匹配项）。谁能帮帮我？

【问题讨论】：

标签： php compare keyword substr

【解决方案1】：

$original_keywords = array("cat", "dog", "mouse");
$possible_keywords1 = preg_split('/,\s*/', "cat, dog, hamster");
echo count(array_intersect($original_keywords, $possible_keywords1))

【讨论】：

【解决方案2】：

$original_keywords = "cat, dog, mouse";
$possible_keywords_1 = "cat, dog, hamster";
$possible_keywords_2 = "cat, sheep, goat";

// Put the input keywords into an array
$keywords = explode(', ', $original_keywords);

// Put all incoming keywords into one big array (you can add as many arrays
// as you want here)
$input = array_merge(
    explode(', ', $possible_keywords_1),
    explode(', ', $possible_keywords_2));

// Count how many times each keywords from $input appears
$count = array_count_values($input);

// Filter out from $count any keyword that is not present in $keywords
$result = array_intersect_key($count, array_flip($keywords));

See it in action.

【讨论】：

【解决方案3】：

您可以使用 explode 和 array_intersect 的组合来做到这一点

以下是开始的代码：

$possible_keywords_1_array = explode(",", $possible_keywords_1); 
$possible_keywords_2_array = explode(",", $possible_keywords_2); 
$matches = count(array_intersect($possible_keywords_1_array, $possible_keywords_2_array));

【讨论】：