查找时间戳超过给定持续时间的相邻 CSV 行答案

【问题标题】：Find adjacent CSV rows whose timestamps exceed a given duration查找时间戳超过给定持续时间的相邻 CSV 行
【发布时间】：2020-02-07 19:14:25
【问题描述】：

我有一个包含以下内容的文件：

"BatchID","BatchName","JobName","ScannerID","DateCreated","DailyCounter"
"12713","9001","fst100","09                  ","2/6/2020 6:21:06 AM","1"
"12714","9002","fst100","09                  ","2/6/2020 6:21:42 AM","2"
"12715","9003","fst100","09                  ","2/6/2020 6:21:58 AM","3"
"12716","9004","fst100","09                  ","2/6/2020 6:22:13 AM","4"
"12717","9005","fst100","09                  ","2/6/2020 6:22:30 AM","5"
"12718","9006","fst100","09                  ","2/6/2020 6:24:54 AM","6"
"12719","9007","fst100","09                  ","2/6/2020 6:25:12 AM","7"
"12720","9008","fst100","09                  ","2/6/2020 6:55:11 AM","8"
"12721","9009","fst100","09                  ","2/6/2020 6:55:27 AM","9"

我想比较创建日期的字段并将相隔 15 分钟或更长时间的行写入文件。

【问题讨论】：

标签： powershell date compare timespan

【解决方案1】：

自：

当您将时间戳字符串转换为 [datetime] (System.DateTime) 时，您的时间戳字符串采用的格式可以按原样识别（除非您的格式列出了日而不是月份首先），
可以直接减去两个[datetime]实例，得到一个[timespan]实例（System.TimeSpan），其.TotalMinutes属性可以查询

解决方案相当简单：

$prevRow = $null
Import-Csv in.csv | ForEach-Object { # Parse the CSV rows into objects and process each
  if ($prevRow -and ([datetime] $_.DateCreated - [datetime] $prevRow.DateCreated).TotalMinutes -gt 15) {
    # Output the previous row and the current row.
    $prevRow; $_
  }
  $prevRow = $_
} # | Export-Csv -NoTypeInformation -Encoding Utf8 out.csv

^{上面会将匹配的行打印到屏幕上；删除 # 以导出到（不同的）CSV 文件。}

注意：如所写，您可能会在输出中出现 duplicate 行，即如果在相邻行 A B C 中，A 和 B 以及 B 和 C 相隔超过 15 分钟，在这种情况下输出 A B B C。

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【讨论】：