我正在创建一个拼字游戏。用户正在输入他们拥有的字母，然后是他们想要创建的单词如果可以创建单词，则返回 true答案

【问题标题】：I'm creating a scrabble game. The user is inputting the letters they have and then the word they want to create Return true if the word can be made我正在创建一个拼字游戏。用户正在输入他们拥有的字母，然后是他们想要创建的单词如果可以创建单词，则返回 true
【发布时间】：2021-09-08 22:47:22
【问题描述】：

#Problem 1
# #inputs
rack=input("what are the characters in your rack?: ")
word=input("what word would you like to create?: ")
#converting the rack to list
rack_list=[]
rack_list[:0]=rack
#Converting word to list
word_list=[]
word_list[:0]=word
#deleting whatever letters word has in it from rack list
for char in rack_list:
    if char ==word_list:
        word_list.remove(char)
#seeing if there are no more letters left in wordlist the word can be created

if len(word_list)==0:
    can_make_word_bool=True
else:
    can_make_word_bool=False    

print(can_make_word_bool)

` 如果单词可以生成，can_make_word_bool 值将返回 true，如果无法生成，则返回 false。我这样做是为了如果用户在机架列表中有这些字母，单词中的任何字母都会从单词列表中删除。如果 word_list 的长度在末尾为 0，这应该意味着这个词可以拼写出来吗？由于某些原因，这些字母没有从单词列表中删除

【问题讨论】：

标签： python coding-style

【解决方案1】：

您输入的是if char == word_list:，而不是if char in word_list:。下面是代码的样子：

#Problem 1
# #inputs
rack=input("what are the characters in your rack?: ")
word=input("what word would you like to create?: ")
#converting the rack to list
rack_list=[]
rack_list[:0]=rack
#Converting word to list
word_list=[]
word_list[:0]=word
print(word_list)
#deleting whatever letters word has in it from rack list
for char in rack_list:
    if char in word_list: ### EDITED HERE
        word_list.remove(char)
        print(word_list)
#seeing if there are no more letters left in wordlist the word can be created

if len(word_list)==0:
    can_make_word_bool=True
else:
    can_make_word_bool=False    

print(can_make_word_bool)

【讨论】：