FastAPI上传多张图片的请求格式

Question

示例

这是我尝试上传图片列表的代码：

import requests
import glob
import cv2

path = glob.glob("test_folder/*", recursive=True) # a list of image's path

lst_img = []
for p in path[:3]:
    # img = cv2.imread(p)
    lst_img.append((p, open(p, 'rb'), "image/jpeg"))

data = {"files": lst_img}

url = "http://localhost:6789/" # url api of app

res = requests.post(url=url, data=data)

print(res.status_code)

print(res.text)

说明

我正在尝试通过 url api 上传图像列表。在这里，我使用请求（python 包），但也许我的请求格式错误，然后我无法发布到 url api。我收到错误代码 422：

"detail":[{"loc":["body","files",0],"msg":"Expected UploadFile, received: <class 'str'>","type":"value_error"}

这是我的请求格式：

{'files': [('test_folder/image77.jpeg', <_io.BufferedReader name='test_folder/image77.jpeg'>, 'image/jpeg'), ('test_folder/image84.jpeg', <_io.BufferedReader name='test_folder/image84.jpeg'>, 'image/jpeg'), ('test_folder/image82.jpeg', <_io.BufferedReader name='test_folder/image82.jpeg'>, 'image/jpeg')]}

我尝试了很多方法，但总是失败。非常感谢你们帮助解决它。

环境

• 操作系统：Linux：（Ubuntu 18.04）
• FastAPI 版本：0.61.1
• 请求版本：2.24.0
• Python 版本：3.7.5

试过了还是不行

lst_img.append(("file", (p, open(p, 'rb'), "image/jpeg")))

我的 FastAPI main.py

from typing import List

from fastapi import FastAPI, File, UploadFile
from fastapi.responses import StreamingResponse, FileResponse

app = FastAPI()

@app.post("/")
async def main(files: List[UploadFile] = File(...)):
    # file_like = open(video_path, mode="rb")
    # return StreamingResponse(file_like, media_type="video/mp4")
    return {"filenames": [file.filename for file in files]}

Answer 1

以下是如何使用 Python 请求和 FastAPI 上传多个文件（图像）的示例。如果您在上传文件时需要发送额外的数据，请查看here。另外，如果您需要async 编写以将图像保存在服务器端，请查看this answer。

app.py

import uvicorn
from fastapi import File, UploadFile, FastAPI
from typing import List

app = FastAPI()


def save_file(filename, data):
    with open(filename, 'wb') as f:
        f.write(data)

@app.post("/upload")
async def upload(files: List[UploadFile] = File(...)):

    # in case you need the files saved, once they are uploaded
    for file in files:
        contents = await file.read()
        save_file(file.filename, contents)

    return {"Uploaded Files": [file.filename for file in files]}
    

if __name__ == '__main__':
    uvicorn.run(app, host='0.0.0.0', port=8000)

test.py

import requests
import glob

paths = glob.glob("images/*", recursive=True) # returns a list of files/pathnames
images = [('files', open(p, 'rb')) for p in paths] # or paths[:3] to select the first 3 images
url = 'http://127.0.0.1:8000/upload'
resp = requests.post(url=url, files=images) 
print(resp.json())

Answer 2

您应该使用request 模块的files 参数来发送文件

import requests
import glob

path = glob.glob("test_folder/*", recursive=True) # a list of image's path

lst_img = []
for p in path[:3]:
    lst_img.append({"files": open(p, 'rb')})

url = "http://localhost:6789/" # url api of app

for data in lst_img:
    res = requests.post(url=url, files=data)
    print(res.status_code)
    print(res.text)