我希望它在不是 0 或 1 时给我错误 [关闭]

Question

#!/usr/bin/python

def open_doors(state):
    (ld, rd, li, ri, lo, ro, cl, ml, gs) = state

    if not(ld == 0 or rd == 0 or li == 0 or ri == 0 and lo == 0 or ro == 0 or cl == 0 or ml == 0):
      raise ValueError("Error: A state is not specified or invalid entry")

    if not(ld == 1 or rd == 1 or li == 1 or ri == 1 and lo == 1 or ro == 1 or cl == 1 or ml == 1):
      raise ValueError("Error: A state is not specified or invalid entry")

    leftDoor = (ld or li or lo)
    rightDoor = (rd or ri or ro)
    if (li and cl):
      leftDoor = 0
    if (ri and cl):
      rightDoor = 0

    if leftDoor and rightDoor and not ml and gs == 'P':
      print("left door and right door open")
    elif leftDoor and not ml and gs == 'P':
      print("open left door")
    elif rightDoor and not ml and gs == 'P':
      print("open right door")
    else:
      print("both doors stay closed")   

open_doors([0,0,1,6,0,0,1,0,'2'])

如果没有指定每个状态，则引发 ValueError， 开关和锁不是 0 或 1 或者 gs 是 不是（'P''R'，'N'，'2'，'3''D'）之一

Answer 1

我愿意

if any((i != 0 and i != 1) for i in state):
  raise ValueError("Error: A state is not specified or invalid entry")

这很简短。

甚至可以改成

valid = set((0, 1))
if any(i not in valid for i in state):
  raise ValueError("Error: A state is not specified or invalid entry")

我不确定这是否是更好的性能或可读性。