pygame中自制的2D碰撞检测不起作用

Question

我正在制作一个类似 tron 的游戏，两个玩家用按键 w、a、s、d 控制他们的角色，玩家 1 和玩家2 控制他们的角色用上、下、左、右。在玩家移动时，用户会留下踪迹，如果对方玩家触及玩家的踪迹，他们就会“出局”。

游戏代码：

from steel2D import *

window = Window(600, 450, "Steel 2D Tutorial")
running = True
char1 = Rect(window, 0, 0, 5, 5, (255, 0, 0))
char2 = Rect(window, 595, 445, 5, 5, (0, 0, 255))
trail1 = []
trail2 = []
red = 0
blue = 0

while running:
    sleep(2)
    keys = OnKeyInput()

    if keys[pygame.K_w]:
        char1.y -= 2.2
        trail1.append(char1)
    if keys[pygame.K_a]:
        char1.x -= 2.2
        trail1.append(char1)
    if keys[pygame.K_s]:
        char1.y += 2.2
        trail1.append(char1)
    if keys[pygame.K_d]:
        char1.x += 2.2
        trail1.append(char1)

    if keys[pygame.K_UP]:
        char2.y -= 2.2
        trail2.append(char2)
    if keys[pygame.K_LEFT]:
        char2.x -= 2.2
        trail2.append(char2)
    if keys[pygame.K_DOWN]:
        char2.y += 2.2
        trail2.append(char2)
    if keys[pygame.K_RIGHT]:
        char2.x += 2.2
        trail2.append(char2)

    if char1.x >= 595:
        char1.x = 595
    if char1.x <= 0:
        char1.x = 0
    if char1.y >= 445:
        char1.y = 445
    if char1.y <= 0:
        char1.y = 0

    if char2.x >= 595:
        char2.x = 595
    if char2.x <= 0:
        char2.x = 0
    if char2.y >= 445:
        char2.y = 445
    if char2.y <= 0:
        char2.y = 0

    char1.draw()
    char2.draw()
    Update()

    for t1, t2 in zip(trail1, trail2):
        if OnRectCollison(t1, t2):
            exit()

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False
            pygame.quit()

在每次按键时，用户轨迹都会被附加到一个列表中，然后循环遍历以检查是否存在冲突。现在它似乎只在玩家的第一条轨迹接触时才会检测到碰撞，没有别的。

steel2D 代码（我的游戏引擎）：

import pygame
from threading import Thread

pygame.init()


def sleep(ms):
    pygame.time.delay(ms)


def Window(w, h, title="steel2D"):
    window = pygame.display.set_mode((w, h))
    pygame.display.set_caption(title)
    return window


def Update():
    pygame.display.update()


def OnKeyInput():
    return pygame.key.get_pressed()


class Rect:
    def __init__(self, window, x, y, w, h, color=(0, 0, 0)):
        self.window = window
        self.x = x
        self.y = y
        self.w = w
        self.h = h
        self.color = color

    def draw(self):
        pygame.draw.rect(self.window, self.color, (self.x, self.y, self.w, self.h))


class Circle:
    def __init__(self, window, x, y, r, color=(0, 0, 0)):
        self.window = window
        self.x = x
        self.y = y
        self.r = r
        self.color = color

    def draw(self):
        pygame.draw.circle(self.window, self.color, (self.x, self.y), self.r, self.r)


def Line(window, color, sx, sy, ex, ey, width=2):
    pygame.draw.line(window, color, (sx, sy), (ex, ey), width)


def OnRectCollison(rect1, rect2):
    if rect1.x < rect2.x + rect2.w and rect1.x + rect1.w > rect2.x and rect1.y < rect2.y + rect2.h and rect1.y + rect1.h > rect2.y:
        return True
    else:
        return False

任何帮助将不胜感激。

Answer 1

有几个问题：

1. 如果您想将头部矩形与trail1 和trail2 中的每个矩形进行比较，zip 是错误的函数。您只会在相同的索引处获得成对的矩形，并且还会删除较长列表的元素。看看这个例子：

   >>> trail1 = [1, 2, 3]
   >>> trail2 = ['a', 'b', 'c', 'd', 'e']
   >>> list(zip(trail1, trail2))
   [(1, 'a'), (2, 'b'), (3, 'c')]
   

   只需遍历跟踪列表中的矩形并检查 char1 或 char2 是否与它们碰撞。

   # I skip the last few rects by slicing the list, otherwise they would collide immediately.
   for trail in trail1[:-5]:
       if OnRectCollison(char1, trail):
           print('collision')
   for trail in trail2:
       if OnRectCollison(char1, trail):
           print('collision')
   

2. 您在移动时将相同的Rect 对象（char1、char2）附加到轨迹列表，因此列表仅包含对头部矩形的引用，因此只有轨迹的头部能够碰撞.

   trail1.append(char1)
   

   改为附加（浅）副本：

   trail1.append(copy.copy(char1))
   

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旁注：碰撞拼写错误。