使用 CoreAnimation 对圆角矩形进行动画处理

Question

伙计们，我有以下代码来生成贝塞尔路径

firstLine.path = UIBezierPath(roundedRect: CGRect(x: frameSize.width / 2.2, y: frameSize.height / 2.6, width: 4, height: 4), cornerRadius: 10).cgPath

我尝试通过将 firstLine 移动到屏幕右侧 x 值并返回到原始位置来为 firstLine 设置动画。但我不知道动画中的 keyPath 用什么。

let animation = CABasicAnimation(keyPath: "??")
animation.toValue = // this should be the position to move?
animation.duration = 0.5 // duration of the animation
animation.timingFunction = CAMediaTimingFunction(name: kCAMediaTimingFunctionEaseOut) // animation curve is Ease Out
animation.fillMode = kCAFillModeBoth // keep to value after finishing
animation.isRemovedOnCompletion = false // don't remove after finishing
animation.autoreverses = true
animation.repeatCount = HUGE

有人可以帮我解决这个问题吗:)

Answer 1

发件人：https://developer.apple.com/reference/quartzcore/cabasicanimation

您使用继承的 init(keyPath:) 方法创建 CABasicAnimation 的实例，指定要在渲染树中进行动画处理的属性的键路径。

您想要的示例：

let animation = CABasicAnimation(keyPath: "position")
animation.fromValue = [startX, startY]
animation.toValue = [destinationX, destinationY]