在 Swift 中调用 webAPI 和致命错误：字典文字包含重复的键答案

【问题标题】：To Call webAPI in Swift & fatal error: dictionary literal contains duplicate keys在 Swift 中调用 webAPI 和致命错误：字典文字包含重复的键
【发布时间】：2014-11-29 10:46:33
【问题描述】：

我已经使用 swift 和 Objective-C 来调用带有参数的 API，我已经在 Objective C 中成功地完成了，但是我在 Swift 中遇到了一个问题来使用它的参数调用 API。

我在两个参数中使用了相同的键，即“密码”。它在 Swift 中不起作用，但在 Objective C 中是正确的。

请指导我并更新我的 Swift 代码。

谢谢

Swift 代码

var params: [String: String] = ["FirstName":name, "ContactNumber":contact, "Email":email, "password": password,"password":repassword,"Rd_UserType":type]


    var request = NSMutableURLRequest(URL: NSURL(string: "http://local.in/api/AccountApi")!)
    var session = NSURLSession.sharedSession()
    request.HTTPMethod = "POST"

    var err: NSError?
    request.HTTPBody = NSJSONSerialization.dataWithJSONObject(params, options: nil, error: &err)
    request.addValue("application/json", forHTTPHeaderField: "Content-Type")
    request.addValue("application/json", forHTTPHeaderField: "Accept")

var task = session.dataTaskWithRequest(request, completionHandler: {data, response, error -> Void in
        println("Response: \(response)")

错误

fatal error: dictionary literal contains duplicate keys

Objective C 代码工作正常。

Objective-C 代码

        NSString *post =[[NSString alloc] initWithFormat:@"FirstName=%@&ContactNumber=%@&Email=%@&password=%@&password=%@&Rd_UserType=%@",Name.text,ContactNumber.text,EmailAddress.text,Password.text,ReTypePassword.text,type];


        NSLog(@"PostData: %@",post);

        NSURL *url=[NSURL URLWithString:@"http://local.in/api/AccountApi"];



        NSLog(@"%@",url);


        NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

        NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];

        NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
        [request setURL:url];
        [request setHTTPMethod:@"POST"];
        [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
        [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
        [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
        [request setHTTPBody:postData];

        //[NSURLRequest setAllowsAnyHTTPSCertificate:YES forHost:[url host]];

        NSError *error = [[NSError alloc] init];
        NSHTTPURLResponse *response = nil;
        NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

        NSLog(@"Response code: %ld", (long)[response statusCode]);

        if ([response statusCode] >= 200 && [response statusCode] < 300)
        {
            NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
            NSLog(@"Response ==> %@", responseData);
        }

【问题讨论】：

您的 Swift 代码与 Obj-C 代码根本不同。在 Obj-C 中，您使用 string 作为发布数据创建请求。在 Swift 中，您使用 JSON 字典 作为发布数据创建请求。

标签： ios objective-c iphone swift ios8

【解决方案1】：

您的 Swift 代码与 Obj-C 代码根本不同。 Swift 等价物到

NSString *post =[[NSString alloc] initWithFormat:@"FirstName=%@&ContactNumber=%@&Email=%@&password=%@&password=%@&Rd_UserType=%@",Name.text,ContactNumber.text,EmailAddress.text,Password.text,ReTypePassword.text,type];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];

应该是这样的

let post = "FirstName=\(Name.text)&ContactNumber=\(ContactNumber.text)&..."
let postData = post.dataUsingEncoding(NSASCIIStringEncoding, allowLossyConversion: true)!
let postLength = "\(postData.length)"

您正在创建一个 JSON 字典作为发布数据。那失败了，因为字典不能有同一个键的两个值。 JSON也可能不是服务器期望什么。

【讨论】：

【解决方案2】：

我已经解决了我的问题并且我已经使用了这个代码。

谢谢。

    let post = String(format: "FirstName=%@&ContactNumber=%@&Email=%@&password=%@&password=%@&Rd_UserType=%@",name,contact,email,password,repassword,type)

    NSLog("PostData: %@",post);

    var url1:NSURL = NSURL(string: "http://local.in/api/AccountApi")!

    var postData:NSData = post.dataUsingEncoding(NSASCIIStringEncoding)!

    var postLength:NSString = String( postData.length )

    var request:NSMutableURLRequest = NSMutableURLRequest(URL: url1)


    request.HTTPMethod = "POST"
    request.HTTPBody = postData
    request.setValue(postLength, forHTTPHeaderField: "Content-Length")
    request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
    request.setValue("application/json", forHTTPHeaderField: "Accept")


    var reponseError: NSError?
    var response: NSURLResponse?

    var urlData: NSData? = NSURLConnection.sendSynchronousRequest(request, returningResponse:&response, error:&reponseError)

    if ( urlData != nil ) {
        let res = response as NSHTTPURLResponse!;

        NSLog("Response code: %ld", res.statusCode);

        if (res.statusCode >= 200 && res.statusCode < 300)
        {
            var responseData:NSString  = NSString(data:urlData!, encoding:NSUTF8StringEncoding)!

            NSLog("Response ==> %@", responseData);

            var error: NSError?

            let jsonData:NSDictionary = NSJSONSerialization.JSONObjectWithData(urlData!, options:NSJSONReadingOptions.MutableContainers , error: &error) as NSDictionary


            let success:NSInteger = jsonData.valueForKey("error") as NSInteger

            //[jsonData[@"success"] integerValue];

            NSLog("Success: %ld", success);

        }

    }

【讨论】：