【问题标题】:Pull out valueForKeys of an inner NSMutableDictionary iOS提取内部 NSMutableDictionary iOS 的 valueForKeys
【发布时间】:2013-02-08 14:42:33
【问题描述】:

好的,我得到一个 Json 提要并将其存储到一个名为 jsonArray 的数组中。然后我循环遍历 jsonArray,取出数组键并将它们存储为字符串。然后,我将这些字符串添加到一个名为 innerDict 的内部字典中,然后使用下面的键将该字典添加到 info 字典中。所以基本上innerDict存储在infoDict里面。

-(void)pointInfo{

infoDict = [[NSMutableDictionary alloc]init];

for (int i = 0; i < jsonArray.count; i++) {

innerDict = [[NSMutableDictionary alloc]init];

info = [[jsonArray objectAtIndex:i]objectForKey:@"inf"];
thePostCode = [[jsonArray objectAtIndex:i]objectForKey:@"pc"];
mail = [[jsonArray objectAtIndex:i]objectForKey:@"mail"];
url = [[jsonArray objectAtIndex:i]objectForKey:@"url"];
type = [[jsonArray objectAtIndex:i]objectForKey:@"items"];

[innerDict setObject:type forKey:@"Items"];
[innerDict setObject:info forKey:@"Info"];
[innerDict setObject:mail forKey:@"Mail"];
[innerDict setObject:url forKey:@"Url"];

[infoDict setObject:innerDict forKey:thePostCode];

}

infoDict 的输出如下所示:

infoDict is {
"ME14 4NN" =     {
    Info = "";
    Items = 4;
    Mail = "";
    Url = "";
};
"ME15 6LG" =     {
    Info = af;
    Items = "0,6,9";
    Mail = "";
    Url = "";
};
"ME15 6YE" =     {
    Info = "";
    Items = "4,5,6,7,11";
    Mail = "";
    Url = "";
};
}

现在我要做的是获取 innerDict 对象的值,即上面的“ME15 6YE”,并将其用作查询以提取 Info、Items、Mail 和 Url 键的关联数据。我已经盯着屏幕看了几个小时,但我就是不明白。

我可以使用下面的方法提取内部字典的最后一个对象,但是我想获取与特定邮政编码关联的所有值,这将是 innerDict 键。目前完全脑筋急转弯!

for (NSMutableDictionary *dictionary in infoDict) {

    NSLog(@"URL %@", [innerDict objectForKey:@"Url"]);
    NSLog(@"MAIL %@", [innerDict objectForKey:@"Mail"]);
    NSLog(@"ITEMS %@", [innerDict objectForKey:@"Items"]);
    NSLog(@"ITEMS %@", [innerDict objectForKey:@"Info"]);

}

【问题讨论】:

  • 一个选项是创建一个自定义对象来存储您的数据,然后将这些对象的实例存储在字典中,键入该(邮政编码?)键值。换句话说,创建一个可以在整个项目中重复使用的模型。
  • @trojanfoe 我确信我可以在最后提到的 for 循环中添加一些简单的东西来提取特定 postCode 的值,但我现在想不出来..
  • 好的,我已经提供了答案,但它似乎太明显了,不正确......

标签: ios ios5 nsdictionary nsmutabledictionary key-value-coding


【解决方案1】:

要获取正确的内部字典,请使用objectForKey

NSDictionary *innerDict = [infoDict objectForKey:@"ME15 6YE"];
NSLog(@"Url %@", [innerDict objectForKey:@"Url"]);
NSLog(@"Mail %@", [innerDict objectForKey:@"Mail"]);
NSLog(@"Items %@", [innerDict objectForKey:@"Items"]);
NSLog(@"Info %@", [innerDict objectForKey:@"Info"]);

【讨论】:

  • 哦,天哪,是的,这很简单,哈哈,因为它是一本内部字典,所以花了很长时间才挂断……谢谢!
【解决方案2】:

也许我误解了什么,但我认为这应该回答你的问题。

您在 for 循环中使用 dictionary,但尝试通过 innerDict 访问它。将其更改为:

for (NSMutableDictionary *dictionary in infoDict) {
    NSLog(@"URL %@", [dictionary objectForKey:@"Url"]);
    NSLog(@"MAIL %@", [dictionary objectForKey:@"Mail"]);
    NSLog(@"ITEMS %@", [dictionary objectForKey:@"Items"]);
    NSLog(@"ITEMS %@", [dictionary objectForKey:@"Info"]);
}

或者,对于单个,

NSMutableDictionary *inner = [infoDict objectForKey:@"POST CODE HERE"];
NSLog(@"URL %@", [inner objectForKey:@"Url"]);
NSLog(@"MAIL %@", [inner objectForKey:@"Mail"]);
NSLog(@"ITEMS %@", [inner objectForKey:@"Items"]);
NSLog(@"ITEMS %@", [inner objectForKey:@"Info"]);

【讨论】:

  • 谢谢你的回答也是正确的,但是木马首先出现了,我会支持你!
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