【发布时间】:2026-01-18 21:50:01
【问题描述】:
对 4.6 中的所有新增功能感到非常兴奋!在查看了大部分更改后,我在 AKMIDICallbackInstrument 中没有看到任何明显不同的地方,但是,我无法再让电话恢复工作了。这是我的实现:
var sequencer: AKSequencer = AKSequencer()
var callbackTrack: AKMusicTrack = AKMusicTrack()
var callbackInst: AKMIDICallbackInstrument = AKMIDICallbackInstrument()
---
public func setupSequencerWithBeats(beats: Int, bpm: Double) {
print("Num beats: \(beats) | BPM: \(bpm)")
sequencer.setTempo(bpm)
callbackTrack = sequencer.newTrack()!
callbackTrack.setMIDIOutput(callbackInst.midiIn)
for i in 0 ..< beats {
callbackTrack.add(noteNumber: MIDINoteNumber(60), velocity: 100, position: AKDuration(beats: Double(i)), duration: AKDuration(beats: 1))
}
callbackInst.callback = {status, noteNumber, velocity in
//Using the new AKMIDIStatus object to unwrap the status and check if it's .noteOn
if let midiStatus = AKMIDIStatus(byte: status), midiStatus.type != .noteOn
{
return
}
// just some delegates to other classes
self.sequencerdDelegate?.didRecieveCallbackFromSequencer(beatNumber: self.beatNumber)
self.beatNumber += 1
}
当我调用sequencer.play() 时,callbackInst 无法再触发回调。我的假设是 setMIDIOutput() 方法有什么变化吗?如果在我的音序器中触发 .noteOn 事件时有更好的方法来获取回调,我很想知道。谢谢大家!
【问题讨论】: