调用带有变量的块是否保证其生命周期将被保留？

Question

我有一些 typedef：

typedef void (^myBlock)(SomeObject);

我有一些对象

@interface SomeObject : NSObject
@end

// Method of some arbitrary class
- (void) someMethod1 {
    SomeObject *someObject = [[SomeObject alloc] init];

    myBlock block = ^(SomeObject obj){
        // When _block(someObject)_ will be called inside someQueue - 
        // Is it guaranteed that someObject will be alive, retained inside me?       

        // Do something complex and involving (or not) obj ...    
    }

    dispatch_async(someQueue, ^{
        // Some bunch of code - after which we are sure that 
        // by the next line someMethod1 will run out, so its scope is lost

        block(someObject);
    });
}

问题放在 block 变量的块中：是否保证我们传递给 someQueue 队列中的块 block 的 someObject 对象会在 block 块内活着并保留？

这个问题是我刚刚提出的问题的一个更复杂的变体：Does a passing of an object to a block guarantee that its lifecycle will be retained?。

Answer 1

该块及其将使用的所有内容都将保留到该块执行之后..它被捕获

Answer 2

我相信您的问题与上一个问题相同。这里唯一的区别是您不是在块内调用方法，而是在调用块。
可能我的回答不够清楚：一切都保留在一个块中，甚至保留一个块。

dispatch_async(someQueue, ^{
    // Some bunch of code - after which we are sure that 
    // by the next line someMethod1 will run out, so its scope is lost

    block(someObject);
});

在你调用someObject的block里面，所以someObject被捕获了。block也被捕获了。