emgu cv矩阵访问行和具有通道c#的cloums答案

【问题标题】：emgu cv matrix access row and cloums with channel c#emgu cv矩阵访问行和具有通道c#的cloums
【发布时间】：2011-08-26 00:21:05
【问题描述】：

如何访问具有指定行、列和通道的矩阵？

Matrix<double> tensor = new Matrix<double>(yMax + 1, xMax, 4); //4 channels
CvInvoke.cvZero(tensor);
for(int k  = 0; k<x.Count; ++k)
{
    double gx = Math.Cos(angle[k] * Math.PI / 180 + 90 * Math.PI / 180 + Math.PI);
    double gy = Math.Sin(angle[k] * Math.PI / 180 + 90 * Math.PI / 180 + Math.PI);
    tensor[y[k], x[k]] = gx * gx; //How can I access other channels?
    tensor.Data[y[k], x[k] + 1] = gx * gy; //How can I access other channels?
    tensor.Data[y[k], x[k] + 2] = gx * gy; //How can I access other channels?
    tensor.Data[y[k], x[k] + 3] = gy * gy; //How can I access other channels?
}

【问题讨论】：

标签： c# matrix channel computer-vision emgucv

【解决方案1】：

我认为你应该看看Split() 方法，然后在通道数组上循环。

【讨论】：

如果您根据我的建议发布代码并将其标记为已回答，这可能会很有用:)

【解决方案2】：

这是从Mat的两个独立通道获取像素值的示例：

var flowResult = new Mat();
CvInvoke.CalcOpticalFlowFarneback(_scaledDownFrameOneColorImagePrev, scaledDownFrameOneColorImage, flowResult, 0.25, 3, 15, 5, 1, 1.2, OpticalflowFarnebackFlag.Default);

var flowResultChannels = flowResult.Split();
var flowResultX = flowResultChannels[0];
var flowResultY = flowResultChannels[1];

for (var r = 0; r < flowResult.Rows; r++)
{
    for (var c = 0; c < flowResult.Cols; c++)
    {
        var xValue = new float[1];
        Marshal.Copy(flowResultX.DataPointer + (((r * flowResultX.Cols) + c) * flowResultX.ElementSize), xValue, 0, 1);

        var yValue = new float[1];
        Marshal.Copy(flowResultY.DataPointer + (((r * flowResultY.Cols) + c) * flowResultY.ElementSize), yValue, 0, 1);

        if (Math.Abs(xValue[0]) > 3 || Math.Abs(yValue[0]) > 3)
        {
            Console.WriteLine("{0} {1}", xValue[0], yValue[0]);
        }
    }
}

【讨论】：