【发布时间】:2015-05-14 11:36:58
【问题描述】:
当通过外部应用程序将记录插入数据库时尝试更新记录时遇到问题。
我需要从应用程序中的用户插入的记录从表 AERO_LOCATIONSTOCKMIN 中获取值 MinimumStock,该表是父位置和资产类型
LOCATIONSTOCKMINID ASSETTYPEID LOCATIONID MINIMUMSTOCK
54000000001 54000000043 43200000357 12.00
54000000002 54000000043 43200000883 6.00
这是目的:当用户尝试在Asset 表上插入记录(通过外部应用程序)时,触发器必须检查用户是否为该Asset 选择了位置。如果是这样,触发器必须检索所选位置的父位置,并检查是否为此 AssetType 和此父位置定义了最低库存。
如果全部满足,触发器必须将字段UDFText01设置为上表中定义的最小库存。
这是我迄今为止尝试过的。触发器很好地检查了需求,但在尝试 UPDATE 并引发以下错误时失败:
The transaction ended in the trigger. The batch has been aborted.
我尝试以多种方式修改 UPDATE 语句,但它们都引发了相同的错误消息。
编辑
按照@Sean Lannge 的建议,我编辑了触发器以管理多个插入。触发器不再显示错误消息,但更改(插入)未保存到数据库中。
ALTER TRIGGER [spectwosuite].[TRI_ASSET_STOCKMIN] ON [spectwosuite].[ASSET]
FOR INSERT AS
BEGIN
IF (UPPER(USER) != 'SPECTWOREPLENG')
DECLARE @assettypeid numeric(15);
DECLARE @assetid numeric(15);
DECLARE @locationid numeric(15);
DECLARE @parentlocationid numeric(15);
DECLARE @stockmin numeric(9,2);
DECLARE @mistock varchar(100);
DECLARE crs_ROWS CURSOR FOR
SELECT ASSETID, ASSETTYPEID, LOCATIONID
FROM inserted;
OPEN crs_ROWS;
FETCH NEXT FROM crs_ROWS INTO @assetid, @assettypeid, @locationid
WHILE (@@FETCH_STATUS = 0)
BEGIN
SELECT @parentlocationID = ParentLocationID FROM Location
LEFT JOIN Asset ON Asset.LocationID = Location.LocationID
WHERE Asset.LocationID = @locationid;
IF NOT EXISTS
(SELECT * FROM Location LEFT JOIN INSERTED AS i ON Location.LocationID = i.LocationID
WHERE Location.LocationID = i.LocationID)
BEGIN
RAISERROR ('Please fill the Location for the Asset.',16,1);
ROLLBACK;
END
ELSE
IF EXISTS (SELECT MinimumStock FROM AERO_LOCATIONSTOCKMIN
WHERE AssetTypeID = @assettypeid AND LocationID = (SELECT ParentLocationID FROM Location WHERE LocationID = @locationID))
BEGIN
SELECT @stockmin = MinimumStock FROM AERO_LOCATIONSTOCKMIN
WHERE AssetTypeID = @assetTypeID AND LocationID =
(SELECT ParentLocationID FROM Location WHERE LocationID = @locationID);
SELECT @mistock= CONVERT(varchar(100),@stockmin);
--RAISERROR (@mistock,16,1);
UPDATE spectwosuite.ASSET
SET UDFText01 = @mistock
FROM
INSERTED I
INNER JOIN spectwosuite.ASSET T ON
T.AssetID = I.AssetID
--UPDATE spectwosuite.ASSET SET UDFText01 = @mistock
-- FROM spectwosuite.ASSET AS A INNER JOIN inserted AS I
-- ON A.AssetID = I.AssetID;
END
ELSE
RAISERROR ('The parent Location for the Asset Type doesn't have minimum stock defined',16,1);
ROLLBACK;
FETCH NEXT FROM crs_ROWS INTO @assetid, @assettypeid, @locationid;
END;
CLOSE crs_ROWS;
DEALLOCATE crs_ROWS;
END;
【问题讨论】:
-
UDFText01 字段是否是用户输入数据的表的列之一(使用外部应用程序?)
-
@S.Krishna 是的。
-
我认为在这种情况下您将需要使用“代替”触发器。看到这个 SO stackoverflow.com/questions/5341584/…
-
但我想让外部应用程序执行自己的
INSERT语句,然后添加我自己的UPDATE语句以将值设置为UDFText01。这可能吗? -
我认为这不是一个好主意。当您使用“而不是”触发器时,插入仍在您的外部应用程序中进行,只是您正在根据您提到的场景添加更多输入。
标签: sql-server triggers insert sql-update