将 XML 解析为 SQL Server 表并将 XHTML 标记保留在 XML 元素中答案

【问题标题】：Parse XML into SQL Server table and keep XHTML markup within XML element将 XML 解析为 SQL Server 表并将 XHTML 标记保留在 XML 元素中
【发布时间】：2020-11-11 20:33:49
【问题描述】：

这个问题是 XML 文件中有 xhtml 标记（请参阅 Example_Code 元素），当我运行 XQuery 时，它似乎去除了标记并只保留了文本。我想将 Example_Code 的值完全存储在 XML 文件中的表中。非常感谢您的阅读。

DECLARE @Xml XML = 
N'
<Demonstrative_Examples xmlns:xhtml="http://www.w3.org/1999/xhtml">>
    <Demonstrative_Example>
        <Intro_Text>This is the intro</Intro_Text>
        <Example_Code Nature="bad">Example 1.1</Example_Code>
        <Body_Text>Body 1.1</Body_Text>
        <Example_Code>   <xhtml:div>String sessionID = generateSessionId();<xhtml:br/>Cookie c = new Cookie("session_id", sessionID);<xhtml:br/>response.addCookie(c);</xhtml:div>
</Example_Code>
    </Demonstrative_Example>
    <Demonstrative_Example>
        <Intro_Text>This is the 2nd intro</Intro_Text>
        <Body_Text>Body 2.1</Body_Text>
        <Example_Code Nature="Good">Example 2.1</Example_Code>
    </Demonstrative_Example>
</Demonstrative_Examples>';

-- just to see
;WITH XMLNAMESPACES ('http://www.w3.org/1999/xhtml' as xhtml)  
SELECT @xml.query('<root>
{
    for $x in /Demonstrative_Examples/Demonstrative_Example
    let $id := count(/Demonstrative_Examples/Demonstrative_Example[. << $x[1]]) + 1
        for $y in $x/*[position() gt 1]
        let $pos := count($x/*[. << $y[1]]) + 1
        let $it := $x/*[local-name()="Intro_Text"]
        return <r id="{$id}" pos="{$pos - 1}" 
            Intro_Text="{$it}" 
            Body_Text="{$y[local-name()="Body_Text"]/text()}" 
            Example_Code="{$y[local-name()="Example_Code"]}"
            Nature="{$y[local-name()="Example_Code"]/@Nature}"></r>
}
</root>') AS xmldata;

-- real deal
;WITH rs AS
(
    SELECT @xml.query('<root>
    {
        for $x in /Demonstrative_Examples/Demonstrative_Example
        let $id := count(/Demonstrative_Examples/Demonstrative_Example[. << $x[1]]) + 1
            for $y in $x/*[position() gt 1]
            let $pos := count($x/*[. << $y[1]]) + 1
            let $it := $x/*[local-name()="Intro_Text"]
            return <r id="{$id}" pos="{$pos - 1}" 
                Intro_Text="{$it}" 
                Body_Text="{$y[local-name()="Body_Text"]/text()}" 
                Example_Code="{$y[local-name()="Example_Code"]/text()}"
                Nature="{$y[local-name()="Example_Code"]/@Nature}"></r>
    }
    </root>') AS xmldata
)
SELECT c.value('@id', 'INT') AS [ID] 
    , c.value('@pos', 'INT') AS [Order]
    , c.value('@Intro_Text', 'VARCHAR(30)') AS [Intro_Text]
    , c.value('@Body_Text', 'VARCHAR(30)') AS [Body_Text]
    , c.value('@Example_Code', 'VARCHAR(30)') AS [Example_Code]
    , c.value('@Nature', 'VARCHAR(30)') AS [Nature]
FROM rs CROSS APPLY xmldata.nodes('/root/r') AS t(c);

这是结果集：

【问题讨论】：

标签： sql-server xml

【解决方案1】：

declare @Xml XML = 
N'
<Demonstrative_Examples xmlns:xhtml="http://www.w3.org/1999/xhtml">
    <Demonstrative_Example>
        <Intro_Text>This is the intro</Intro_Text>
        <Example_Code Nature="Bad">Example 1.1</Example_Code>
        <Body_Text>Body 1.1</Body_Text>
        <Example_Code><xhtml:div>String sessionID = generateSessionId();<xhtml:br/>Cookie c = new Cookie("session_id", sessionID);<xhtml:br/>response.addCookie(c);</xhtml:div></Example_Code>
    </Demonstrative_Example>
    <Demonstrative_Example>
        <Intro_Text>This is the 2nd intro</Intro_Text>
        <Body_Text>Body 2.1</Body_Text>
        <Example_Code Nature="Good">Example 2.1</Example_Code>
        <e4>e4</e4>        
        <e5>e5</e5>
        <e6>e6</e6>
        <e7>e7</e7>
        <e8>e8</e8>                        
        <Example_Code Nature="Ugly">examplecode position9 <xhtml:div>String sessionID = generateSessionId();<xhtml:br/>Cookie c = new Cookie("session_id", sessionID);<xhtml:br/>response.addCookie(c);</xhtml:div></Example_Code>
    </Demonstrative_Example>
</Demonstrative_Examples>';

select 
    s.example_order_id,
    s.position_in_example,
    case s.elementname when N'Intro_Text' then s.nodecontent end as IntroText,
    case s.elementname when N'Example_Code' then s.nodecontent end as ExampleCode,
    case s.elementname when N'Body_Text' then s.nodecontent end as BodyText,
    case s.elementname when N'Example_Code' then s.attributenature end as ExampleNature 
from
(
    select 
        dense_rank() over(order by d.ex) as example_order_id,
        row_number() over(partition by d.ex order by ex.el) as position_in_example,
        ex.el.value('local-name(.)[1]', 'nvarchar(100)') as elementname,
        ex.el.value('@Nature[1]', 'nvarchar(30)') as attributenature,
        cast(ex.el.query('node()') as nvarchar(max)) as nodecontent
    from @Xml.nodes('Demonstrative_Examples/Demonstrative_Example') as d(ex)
    outer apply d.ex.nodes('*') as ex(el)
) as s
where s.elementname in (N'Intro_Text', N'Example_Code', N'Body_Text');

【讨论】：

【解决方案2】：

要在 XHTML/XML 时保留 <Example_Code> 元素值，您需要在源 XML 中使用 CDATA 部分。请看下文。

我做了一些额外的修改：

已注释掉命名空间声明。在这种情况下不需要它。
将@Example_Code 的大小增加到VARCHAR(MAX) 以容纳冗长的值。

SQL

DECLARE @Xml XML = 
N'<Demonstrative_Examples xmlns:xhtml="http://www.w3.org/1999/xhtml">
    <Demonstrative_Example>
        <Intro_Text>This is the intro</Intro_Text>
        <Example_Code Nature="bad">Example 1.1</Example_Code>
        <Body_Text>Body 1.1</Body_Text>
        <Example_Code><![CDATA[
            <xhtml:div>String sessionID = generateSessionId();<xhtml:br/>Cookie c = new Cookie("session_id", sessionID);<xhtml:br/>response.addCookie(c);</xhtml:div>
        ]]>
        </Example_Code>
    </Demonstrative_Example>
    <Demonstrative_Example>
        <Intro_Text>This is the 2nd intro</Intro_Text>
        <Body_Text>Body 2.1</Body_Text>
        <Example_Code Nature="Good">Example 2.1</Example_Code>
    </Demonstrative_Example>
</Demonstrative_Examples>';

-- just to see
--;WITH XMLNAMESPACES ('http://www.w3.org/1999/xhtml' as xhtml)  
SELECT @xml.query('<root>
{
    for $x in /Demonstrative_Examples/Demonstrative_Example
    let $id := count(/Demonstrative_Examples/Demonstrative_Example[. << $x[1]]) + 1
    let $it := $x/*[local-name()="Intro_Text"]
        for $y in $x/*[position() gt 1]
        let $pos := count($x/*[. << $y[1]]) + 1
        return <r id="{$id}" pos="{$pos - 1}" 
            Intro_Text="{$it}" 
            Body_Text="{$y[local-name()="Body_Text"]/text()}" 
            Example_Code="{$y[local-name()="Example_Code"]}"
            Nature="{$y[local-name()="Example_Code"]/@Nature}"></r>
}
</root>') AS xmldata;

-- real deal
;WITH rs AS
(
    SELECT @xml.query('<root>
    {
        for $x in /Demonstrative_Examples/Demonstrative_Example
        let $id := count(/Demonstrative_Examples/Demonstrative_Example[. << $x[1]]) + 1
        let $it := $x/*[local-name()="Intro_Text"]
            for $y in $x/*[position() gt 1]
            let $pos := count($x/*[. << $y[1]]) + 1
            return <r id="{$id}" pos="{$pos - 1}" 
                Intro_Text="{$it}" 
                Body_Text="{$y[local-name()="Body_Text"]/text()}" 
                Example_Code="{$y[local-name()="Example_Code"]/text()}"
                Nature="{$y[local-name()="Example_Code"]/@Nature}"></r>
    }
    </root>') AS xmldata
)
SELECT c.value('@id', 'INT') AS [ID] 
    , c.value('@pos', 'INT') AS [Order]
    , c.value('@Intro_Text', 'VARCHAR(30)') AS [Intro_Text]
    , c.value('@Body_Text', 'VARCHAR(30)') AS [Body_Text]
    , c.value('@Example_Code', 'VARCHAR(MAX)') AS [Example_Code]
    , c.value('@Nature', 'VARCHAR(30)') AS [Nature]
FROM rs CROSS APPLY xmldata.nodes('/root/r') AS t(c);

【讨论】：