SQL Server 2008 R2：PIVOT 查询中的列名无效

Question

我有一个动态数据透视查询，我想对我知道存在于 transaction_table 中的 businessaccountnumber 进行数据透视，但它一直返回“无效的列名 'bizi'。”- 对于第 1 行。

DECLARE @Output nvarchar(max) = N''
DECLARE @PivotList varchar(max)


SELECT
  @PivotList = COALESCE(@PivotList + ', ', N'') + N'[' + bizid + N']'

FROM (SELECT DISTINCT
  BusinessAccountNumber [bizid]
FROM transaction_table
WHERE postingdate BETWEEN '1/01/2015' AND '2/01/2015'
) AS CustProds;

SET @Output = 'SELECT [bizName],[bizi]
    , ' + @PivotList + '
FROM  ( select businessname as [bizName],businessaccountnumber as [bizi],
        sum((Transactionamount*(-1))) as [Transactionamount] 
        FROM transaction_table
        WHERE postingdate between ''1/01/2015'' and ''2/01/2015''
        GROUP BY businessaccountnumber,businessname) as P
PIVOT ( SUM(Transactionamount) FOR P.bizi IN (' + @PivotList + ') ) AS PVT'

EXEC sp_executesql @Output;

编辑：感谢 Backs 指出我的错误，但现在我有一个新错误。

我正在寻找的输出是：

Date      | bizid12| bizid13| bizid14...
01/01/2015|  $1    | $3     | $56
01/02/2015| $12    | $34    | $3
.....


DECLARE @Output nvarchar(max) = N''
DECLARE @PivotList varchar(max)


SELECT
  @PivotList = COALESCE(@PivotList + ', ', N'') + N'[' + bizid + N']'

FROM (SELECT DISTINCT
  BusinessAccountNumber [bizid]
FROM transaction_table
WHERE postingdate BETWEEN '1/01/2015' AND '2/01/2015'
) AS CustProds;

SET @Output = 'SELECT [sp_date]
    , ' + @PivotList + '
FROM  ( select Convert(varchar,postingdate,101) as [sp_date] 
        ,businessaccountnumber as [bizi],
        sum((Transactionamount*(-1))) as [Transactionamount] 
        FROM transaction_table
        WHERE postingdate between ''1/01/2015'' and ''2/01/2015''
        GROUP BY businessaccountnumber) as P
PIVOT ( SUM(Transactionamount) FOR P.bizi IN (' + @PivotList + ') ) AS PVT'

EXEC sp_executesql @Output;

错误现在说：

消息 8180，第 16 级，状态 1，第 1 行
无法准备报表。

消息 102，第 15 级，状态 1，第 1 行
“Qry12090”附近的语法不正确。

消息 1056，第 15 级，状态 1，第 1 行
选择列表中的元素数超过了允许的最大元素数 4096。

Answer 1

您不能在查询 SELECT [bizName],[bizi] 中使用它在 PIVOT FOR P.bizi IN 中选择 bizi。从 select 语句中删除 [bizi]