【发布时间】：2018-06-12 14:17:22
【问题描述】：
仍在学习 PHP，所以这可能和其他人一样，但有问题。 我想在前一个屏幕上单击编辑，并在该窗口打开时打开一个更新记录窗口（如下），它将选择以前的标准，但允许用户更改记录。当部门和事物从其他 SQL Server 表中提取时，我在更新屏幕中有多个下拉列表。它不允许我将它们全部放在下拉列表中，以便在更新记录需要时选择新标准。
我只是不确定我可能需要使用的代码，因为开始记录页面设置为从 php 代码中的 sql server 拉取下拉菜单并且它可以工作。不确定为什么选择编辑时不会从视图屏幕中拉动信息以提取已选择的交易和标准。
<?php
require('dbcon.php');
include("header.php");
$transaction_id = $_REQUEST['transaction_id'];
$sql = "SELECT * FROM [Transaction]where
transaction_id='" . $transaction_id . "'";
$query = sqlsrv_query($conn, $sql);
$query_display = sqlsrv_query($conn, $sql);
$row = sqlsrv_fetch_array($query);
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Update Transaction</title>
<link rel="stylesheet" href="css/style.css" />
</head>
<body>
<div class="form">
<h1>Update Transaction</h1>
<?php
$status = "";
if (isset($_POST['new']) && $_POST['new'] == 1) {
$transaction_id = $_REQUEST['transaction_id'];
$fund = $_REQUEST['fund'];
$department = $_REQUEST['department'];
$code_name = $_REQUEST['code_name'];
$budget_year = $_REQUEST['budget_year'];
$entry_date = $_REQUEST['entry_date'];
$project_name = $_REQUEST['project_name'];
$item_desc = $_REQUEST['item_desc'];
$amount = $_REQUEST['amount'];
$detail = $_REQUEST['detail'];
$PO = $_REQUEST['PO'];
$modified = $_REQUEST['modified'];
$update = "update [Transaction] set
fund='" . $fund . "',
department='" . $department . "',
code_name='" . $code_name . "',
budget_year='" . $budget_year . "',
entry_date='" . $entry_date . "',
project_name='" . $project_name . "',
item_desc='" . $item_desc . "',
amount='" . $amount . "',
detail='" . $detail . "',
PO='" . $PO . "'
where transaction_id='" . $transaction_id . "'";
sqlsrv_query($conn, $sql);
$status = "Record Updated Successfully. </br></br>
<a href='transactions.php'>View Updated Record</a>";
echo '<p style="color:#FF0000;">' . $status . '</p>';
} else {
?>
<div>
<form name="form" method="post" action="">
<input type="hidden" name="new" value="1" />
<input name="transaction_id" type="hidden" value="<?php echo $row['transaction_id']; ?>" />
<p>Fund:
<?php
echo "<select name= 'fund' class='form-control selectpicker' onChange='getState(this.value)' Required>";
$sql = "SELECT * FROM Funding";
$query = sqlsrv_query($conn, $sql);
$query_display = sqlsrv_query($conn, $sql);
while ($row = sqlsrv_fetch_array($query_display, SQLSRV_FETCH_ASSOC)) {
if ($row['fund'] == "Operational") {
$selected = ' selected="selected"';
} else {
$selected = "";
}
echo '<option value=" ' . $row['fund'] . '"' . (($row['fund'] == "Operational") ? ' selected="selected"' : "") . '>' . $row['fund'] . '</option>';
echo '<option value= " ' . $row['fund'] . ' ">' . $row['fund'] . '</option>';
continue;
}
?>
</p>
<p>Department:
<?php
echo "<select name= 'department' class='form-control selectpicker' onChange='getState(this.value)' Required>";
$sql = "SELECT * FROM Department";
$query = sqlsrv_query($conn, $sql);
$query_display = sqlsrv_query($conn, $sql);
while ($row = sqlsrv_fetch_array($query_display, SQLSRV_FETCH_ASSOC)) {
echo "<option selected='selected' value='" . $row['department'] . "'>" . $row['department'] . '</option>';
continue;
}
echo "<option value='" . $row['department'] . "'>" . $row['department'] . '</option>';
?>
</p>
<p>Object Code:
<?php
echo "<select name= 'code_name' class='form-control selectpicker' onChange='getState(this.value)' Required>";
echo '<option value="$code_name">' . '--Select Object Code' . '</option>';
$sql = "SELECT code_name FROM Object_Code";
$query = sqlsrv_query($conn, $sql);
$query_display = sqlsrv_query($conn, $sql);
while ($row = sqlsrv_fetch_array($query_display, SQLSRV_FETCH_ASSOC)) {
echo "<option selected='selected' value='" . $row['code_name'] . "'>" . $row['code_name'] . '</option>';
continue;
}
echo "<option value='" . $row['code_name'] . "'>" . $row['code_name'] . '</option>';
?>
</p>
<p>Budget Year:
<select name= 'budget_year' class='form-control selectpicker' onChange='getState(this.value)' Required>
<option selected="selected" value="2018-2019">2018-2019</option>
<option value="2017-2018">2017-2018</option>
<option value="2019-2020">2019-2020</option>
<option value="2020-2021">2020-2021</option>
<option value="2021-2022">2021-2022</option>
<option value="2022-2023">2022-2023</option>
<option value="2023-2024">2023-2024</option>
<option value="2024-2025">2024-2025</option>
<option value="2025-2026">2025-2026</option>
<option value="2026-2027">2026-2027</option>
<option value="2027-2028">2027-2028</option>
<option value="2028-2029">2028-2029</option>
<option value="2029-2030">2029-2030</option>
</select>
</p>
<p>Transaction Entry Date:
<input type="date" name="entry_date" />
</p>
<p>Project:
<?php
echo "<select name= 'project_name' class='form-control selectpicker' onChange='getState(this.value)' Required>";
$sql = "SELECT project_name FROM Project";
$query = sqlsrv_query($conn, $sql);
$query_display = sqlsrv_query($conn, $sql);
while ($row = sqlsrv_fetch_array($query_display, SQLSRV_FETCH_ASSOC)) {
echo '<option value=" ' . $row['project_name'] . ' ">' . $row['project_name'] . '</option>';
continue;
}
?>
</p>
<p>Description:
<input type="text" name="item_desc">
</p>
<p>Amount:
<input type="number" name="amount" min="0" max="9999999" step="0.01" size ="7" />
</p>
<p>Detail:
<td><textarea name="detail"></textarea>
</p>
<p>PO:
<input type="text" name="PO" />
</p>
<p>
<input name="submit" type="submit" value="Update" />
</p>
</form>
<?php } ?>
</div>
</div>
</body>
</html>
【问题讨论】：
-
@LiamG 不确定我能不能带你去
-
我对您的问题是什么感到有点困惑？问题是交易的更新吗？还是创建一个新的？
-
更新当前的。例如，输入时的详细信息和部门是错误的。我想单击编辑按钮打开更新屏幕，它具有最初输入的内容，然后让我选择更新所需的字段。唯一的事情是下拉列表（基金、部门、对象代码、项目名称和预算年份都来自 sql server 中的表。）它不允许我像在原始输入表单中那样添加这些下拉列表来拉从数据库中更新事务表以显示更新的行。
-
所以在上一页，编辑按钮链接是这样的：
editTransaction.php?id=25 -
@LiamG 看看我的回答，看看你的想法，也许我解释不正确
标签： php sql-server sqlsrv