SSRS比较记录的多个详细信息行

Question

这是我在 SSRS 中面临的一个难题，我有点难过。这是我正在尝试创建的业务逻辑。

在确定正确的实验室天数时，请使用以下逻辑：

如果一个案例有多个同一个BacklogGroup的明细项，Daysinlab = Max(DaysinlabGDL)

如果项目来自不同的 BackLogGroups 对每个 BackLogGroups 的 DaysInLabGDL 求和以获得 DaysInLab 数量。

例如：

Case ID         Back Log Group  Days    Calc Days
                                In Lab          
4595549         EMAX            5   7   
4595550         EMAX            5   2   
4595551         CLINICAL ZIRC   5   3   
4595552         BruxZir H       5   3   
4595559         Implant SS      5   4   
4595559         IMPLANTCA       8   8

我在 Calc 天使用的表达式是这样的：

=iif(Fields!CaseID.Value = Previous(Fields!CaseID.Value) and Fields!BackLogGroup.Value <> Previous(Fields!BackLogGroup.Value),Fields!ActualDaysInLab.Value + Previous(Fields!ActualDaysInLab.Value),Max(Fields!ActualDaysInLab.Value))

本质上，我要做的是比较案例中的详细记录，如果每个详细记录的积压组不同（可能有超过 2 个详细记录/案例），则将实验室列中的天数相加.如果详细记录的积压组相同，那么我想在实验室中取 max() 天数。

如果有 3 个详细记录且两个具有相同的积压组的情况，则取其中的最大值并将它们添加到另一个。

因此，在上述案例中，caseID 4595559 的计算天数对于两个详细记录都应为 13 (5+8)。但由于某种原因，我不明白这一点。我最后一个是 4 岁，一个是 8 岁。

如果有什么不同，这里是创建数据集的 SQL 查询：

Declare @StartDate Datetime 
Declare @EndDate Datetime 
Set @StartDate = '12/01/2013'
Set @EndDate = GetDate()

SELECT      
        cp.CaseID
            ,c.DateIn
            ,c.DateInvoiced
            ,cp.ProductID
            ,p.BackLogGroup
            ,sra.SourceCategory
            ,sra.DaysInLabGDL
            ,DATEDIFF(DAY,c.DateIn,c.DateInvoiced) AS ActualDaysInLab
            ,dbo.GL_GetBusinessDayCount(c.DateIn,c.DateInvoiced) AS WorkingDays

FROM  dbo.CaseProducts cp WITH (NOLOCK)
            INNER JOIN dbo.Cases c WITH (NOLOCK)
                  ON cp.CaseID = c.CaseID
            LEFT OUTER JOIN dbo.Products p WITH (NOLOCK)
                  ON cp.ProductID = p.ProductID
            LEFT OUTER JOIN dbo.SalesReAllocation sra WITH (NOLOCK)
                  ON p.ProductID = sra.ProductID
WHERE 
p.BackLogGroup IS NOT NULL
AND 
c.DateInvoiced IS NOT NULL
AND        

c.DateIn between @StartDate and @EndDate

Order by 
cp.CaseID

我希望这很清楚。如果不让我知道，我会尽力澄清。

提前致谢。

Answer 1

我将您的第一个结果集称为t（为方便起见）。

我认为您的问题的解决方案是双重聚合：

select CaseId, sum(DaysInLab) as DaysInLab
from (select CaseID, BackLogGroup, max(DaysInLabGDL) as DaysInLab
      from t
      group by CaseId, BackLogGroup
     ) blg
group by CaseId;

Answer 2

所以这是最终查询。感谢@Gordon Linoff 的帮助。它让我走上了正确的道路。

Declare @StartDate Datetime 
Declare @EndDate Datetime 
Set @StartDate = '12/01/2013'
Set @EndDate = GetDate()
With t as
(
SELECT      
            --count(cp.caseID) as CaseCount
            cp.CaseID
            ,c.DateIn
            ,c.DateInvoiced
            ,cp.ProductID
            ,p.BackLogGroup
            ,sra.SourceCategory
            ,sra.DaysInLabGDL
            ,DATEDIFF(DAY,c.DateIn,c.DateInvoiced) AS ActualDaysInLab
            ,dbo.GL_GetBusinessDayCount(c.DateIn,c.DateInvoiced) AS WorkingDays

FROM  dbo.CaseProducts cp WITH (NOLOCK)
            INNER JOIN dbo.Cases c WITH (NOLOCK)
                  ON cp.CaseID = c.CaseID
            LEFT OUTER JOIN dbo.Products p WITH (NOLOCK)
                  ON cp.ProductID = p.ProductID
            LEFT OUTER JOIN dbo.SalesReAllocation sra WITH (NOLOCK)
                  ON p.ProductID = sra.ProductID
WHERE 
p.BackLogGroup IS NOT NULL
AND 
c.DateInvoiced IS NOT NULL
AND        
--cp.CaseID = 4595187
c.DateIn between @StartDate and @EndDate
)

select blg.CaseID, DateIn, DateInvoiced, sum(DaysInLab) as DaysInLab, blg2.BackLogGroup, blg2.Workingdays, blg2.Workingdays - sum(Daysinlab) as DaysOver
from (select CaseID, BackLogGroup, max(DaysInLabGDL) as DaysInLab, WorkingDays
      from t
      group by CaseId,  BackLogGroup, WorkingDays
     ) blg
     Inner Join (Select CaseID, DateIn, DateInvoiced, BackLogGroup, WorkingDays 
                 from t
                 group by CaseID, DateIn, DateInvoiced, BackLogGroup, WorkingDays
                 ) blg2 on blg.CaseID = blg2.CaseId

group by blg.CaseId, DateIn, DateInvoiced, blg2.BackLogGroup, blg2.Workingdays

having blg2.workingdays > sum(Daysinlab)