SQL Query 显示员工姓名及其对应部门

Question

以下是我的CREATE TABLE 脚本：

CREATE TABLE Person 
( 
   ID INT Primary Key Identity (1,1), 
   LastName nVarchar (20) not NULL, 
   FirstName nVarchar (20) not NULL, 
   MiddleName nVarchar (20), 
   BirthDate DateTime not NULL, 
   Age INT not NULL, 
   Check (Age18) 
); 

CREATE TABLE Department 
( 
   ID INT Primary Key Identity (1,1), 
   DepartmentName nVarchar (50) Unique, 
   DepartmentCode nVarchar (20) Unique, 
   IsActive Bit Default (1) 
); 

CREATE TABLE Employee 
( 
   ID INT Primary Key Identity (1,1), 
   PersonId INT Foreign Key REFERENCES Person, 
   DepartmentId INT Foreign Key REFERENCES Department, 
   Salary Decimal (18,2), 
   Check (Salary10000), 
   IsActive Bit Default (1) 
); 

以下是我的INSERT 脚本：

INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Dela Cruz','Juan',NULL,01/01/199,22) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Dela Cerna','Pedro','Juan',11/01/1993,21) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Villaflores','Rachel','Diacoma',10/7/1990,24) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Abendan','Marnell',NULL,03/15/1989,25) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Oplado','Aiza','Tapayan',11/18/1993,21) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Loreto','Desire','Talingting',06/10/1993,21) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Magbanua','Prince Laurence','Rallos',05/25/1992,22) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Locsin','Franz Cyril',NULL,02/14/1993,21) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Dela Pena','Precious',NULL,01/01/199,21) 

 INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('ITDepartment','ItDept',1) 
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('EngineeringDepartment','EDept',1) 
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('ComputerScienceDepartment','CSDept',1) 
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('InformationSystemDepartment','ISDept',1) 
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('BusinessAdministrationDepartment','BADept',1) 
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('ElementaryDepartment','ElemDept',1) 

 INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (1,2,12000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (2,4,10001,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (3,6,13000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (4,1,25000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (5,3,15000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (6,5,10002,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (7,1,56000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (8,4,14000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (9,6,15900,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (2,4,12300,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (4,1,13500,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (6,3,14300,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (8,5,12500,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (1,2,11460,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (3,4,10910,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (5,6,10001,1) 

以下是我的选择脚本：

SELECT 
    Person.LastName, Department.DepartmentName 
FROM 
    Person, Department 
FULL OUTER JOIN 
    Employee ON Employee.PersonId = Employee.DepartmentId 

这是不正确的结果。我不知道什么是正确的。这是我第一次做JOINS。

Dela Cruz   BusinessAdministrationDepartment 
Dela Cerna  BusinessAdministrationDepartment 
Villaflores BusinessAdministrationDepartment 
Abendan BusinessAdministrationDepartment 
Oplado  BusinessAdministrationDepartment 
Loreto  BusinessAdministrationDepartment 
Magbanua    BusinessAdministrationDepartment 
Locsin  BusinessAdministrationDepartment 
Dela Pena   BusinessAdministrationDepartment 
Dela Cruz   ComputerScienceDepartment 
Dela Cerna  ComputerScienceDepartment 
Villaflores ComputerScienceDepartment 
Abendan ComputerScienceDepartment 
Oplado  ComputerScienceDepartment 
Loreto  ComputerScienceDepartment 
Magbanua    ComputerScienceDepartment 
Locsin  ComputerScienceDepartment 
Dela Pena   ComputerScienceDepartment 

我在计算机科学系停了下来，因为它太长了。我怎样才能做到这一点？请帮忙。谢谢！ :)

Answer 1

你在找这个吗：-

Select  p.LastName, d.DepartmentName
From    Employee As e
        Join Person As p On e.PersonId = p.Id
        JOin Department As d On e.DepartmentId = d.ID

Answer 2

SELECT Person.LastName, Department.DepartmentName FROM Employee INNER JOIN Person ON Employee.PersonId = Person.ID INNER JOIN Department ON Employee.DepartmentId = Department.ID