如何从事件循环外部（即从 python-telegram-bot 线程）发送带有 discord.py 的消息？

Question

我想使用库 python-telegram-bot 和 discord.py（版本 1.0.0）制作一个在 discord 和 telegram 之间进行通信的机器人。然而问题是 discord.py 使用异步函数和 python-telegram-bot 线程。使用下面的代码，在不和谐中发布的消息一切正常（机器人将它们正确地发送到电报），但是反过来不起作用（机器人从电报中获取消息并将其发送到不和谐）。我以前在尝试在同步函数中运行不和谐channel.send 函数时遇到语法/运行时错误问题（因此要么只返回一个生成器对象，要么抱怨我不能在同步函数中使用await）。然而，与此同时，python-telegram-bot 的MessageHandler 需要一个同步函数，所以当给他一个异步函数时，Python 抱怨说，异步函数从未调用过“await”。 我现在尝试使用 asgiref 库中的 async_to_sync 方法从 MessageHandler 运行我的异步 broadcastMsg，但是代码仍然没有将消息发送到不和谐！它似乎正确调用了该函数，但仅在行 print('I get to here') 之前。没有显示错误，也没有不和谐的消息弹出。我想这与我必须将函数注册为 discord.py 事件循环中的任务这一事实有关，但是注册仅在它发生在 botDiscord.run(TOKENDISCORD) 执行之前才有效，这当然必须在之前发生. 所以把我的问题归结为一个问题： 我如何能够从另一个线程（来自电报MessageHandler）与 discord.py 事件循环进行交互。或者如果这是不可能的：如何在不进入 discord.py 事件循环的情况下使用 discord.py 发送消息？

感谢您的帮助

import asyncio
from asgiref.sync import async_to_sync
from telegram import Message as TMessage
from telegram.ext import (Updater,Filters,MessageHandler)
from discord.ext import commands
import discord

TChannelID = 'someTelegramChannelID'
DChannel = 'someDiscordChannelObject'

#%% define functions / commands
prefix = "?"
botDiscord = commands.Bot(command_prefix=prefix)
discordChannels = {}


async def broadcastMsg(medium,channel,message):
    ''' 
    Function to broadcast a message to all linked channels.
    '''
    if isinstance(message,TMessage):
        fromMedium = 'Telegram'
        author = message.from_user.username
        channel = message.chat.title
        content = message.text
    elif isinstance(message,discord.Message):
        fromMedium = 'Discord'
        author = message.author
        channel = message.channel.name
        content = message.content
    # check where message comes from        
    textToSend = '%s wrote on %s %s:\n%s'%(author,fromMedium,channel,content)
    # go through channels and send the message
    if 'telegram' in medium:
        # transform channel to telegram chatID and send
        updaterTelegram.bot.send_message(channel,textToSend)

    elif 'discord' in medium:
        print('I get to here')
        await channel.send(textToSend)

    print("I do not get there")


@botDiscord.event
async def on_message(message):
    await broadcastMsg('telegram',TChannelID,message)

def on_TMessage(bot,update):
    # check if this chat is already known, else save it
    # get channels to send to and send message
    async_to_sync(broadcastMsg)('discord',DChannel,update.message)


#%% initialize telegram and discord bot and run them
messageHandler = MessageHandler(Filters.text, on_TMessage)
updaterTelegram = Updater(token = TOKENTELEGRAM, request_kwargs={'read_timeout': 10, 'connect_timeout': 10})
updaterTelegram.dispatcher.add_handler(messageHandler)
updaterTelegram.start_polling()
botDiscord.run(TOKENDISCORD)  

Answer 1

如何在不进入 discord.py 事件循环的情况下使用 discord.py 发送消息？

要从事件循环线程外部安全地调度协程，请使用asyncio.run_coroutine_threadsafe：

_loop = asyncio.get_event_loop()

def on_TMessage(bot, update):
    asyncio.run_coroutine_threadsafe(
        broadcastMsg('discord', DChannel, update.message), _loop)

Answer 2

您可以尝试将它们拆分为 2 个单独的 *.py 文件。

t2d.py #telegram 不和谐

import subprocess
from telethon import TelegramClient, events, sync

api_id = '...'
api_hash = '...'

with TelegramClient('name', api_id, api_hash) as client:     
    @client.on(events.NewMessage()) #inside .NewMessage() you can put specific channel like: chats="test_channel"
    async def handler(event):        
        print('test_channel raw text: ', event.raw_text) #this row is not necessary

        msg = event.raw_text

        subprocess.call(["python", "s2d.py", msg])

    client.run_until_disconnected()

s2d.py #发送到不和谐

import discord, sys

my_secret = '...'

clientdiscord = discord.Client()

@clientdiscord.event
async def on_ready():
    #print('We have logged in as {0.user}'.format(clientdiscord)) #this row is not necessary

    channel = clientdiscord.get_channel(123456789) # num of channel where you want to write message

    msg = sys.argv[1] #grab message
    
    msg = 's2d: ' + msg #only for test, you can delete this row 
    
    await channel.send(msg)

    quit() # very important quit this bot 

    
clientdiscord.run(my_secret)

会慢一点（子进程会造成延迟），但很容易解决