Python 3.6 Discord bot Bot 事件冲突

Question

所以我有两个机器人事件 用“k”响应消息“k”的一种 一个简单的猜测我的数字在 1-10 之间 问题是它们发生冲突，只有一个有效（下面的那个）IDK 我所缺少的。代码：

@client.event
async def on_message(message):
    # we do not want the bot to reply to itself
    if message.author == client.user:
        return
    if message.author.bot: return
    if message.content==('k'):
        msg = 'k'.format(message)
        await client.send_message(message.channel, msg)

    await client.process_commands(message)




@client.event
async def on_message(message):
    # we do not want the bot to reply to itself
    if message.author == client.user:
        return

    if message.content.startswith('!guess'):
        await client.send_message(message.channel, 'Guess a number     between 1 to 10')

        def guess_check(m):
            return m.content.isdigit()

        guess = await client.wait_for_message(timeout=10.0,    author=message.author, check=guess_check)
        answer = random.randint(1, 10)
        if guess is None:
            fmt = 'Sorry, you took too long. It was {}.'
            await client.send_message(message.channel,     fmt.format(answer))
            return
        if int(guess.content) == answer:
            await client.send_message(message.channel, 'You are right!')
        else:
            await client.send_message(message.channel, 'Sorry. It is     actually {}.'.format(answer))

    await client.process_commands(message)

那么我怎样才能让它们不冲突呢？

Answer 1

您已经定义了函数on_message() 两次。

为了演示这个问题，如果我运行以下代码，您希望输出是什么？

def f(x):
    print(x)

def f(x):
    print('Nothing useful')

f(3)

您的代码中也存在同样的问题。

假设 discord 框架会在收到消息时调用名为 on_message() 的函数，您需要有 一个 on_message() 函数来处理 any 输入。因此，它看起来像这样：

@client.event
async def on_message(message):
    # we do not want the bot to reply to itself
    if message.author == client.user:
        return

    if message.content==('k'):
        ...

    if message.content.startswith('!guess'):
        ...

如果你觉得特别时髦，你可以将 if 块的内容分解成它们自己的函数，以使脚本更易于阅读，但我将把它留给你作为练习，一旦你让其余部分正常工作。