将数据组织成多列 SQL

Question

我有一个包含超过 500 万客户的表，其中包含历史活动数据，如下例所示：

Customer ID	PART_ID	Activity
12345	202012	2
12345	202101	0
12345	202102	5

我想将此数据转换为多列；行中的客户、列中的日期及其各自的活动信息。

我编写了下面的代码，但不是为单个客户创建单行，而是客户重复，我得到一个这样的表：

Customer ID	202012	202101	202102
12345	1	0	0
12345	0	0	0
12345	0	0	1

代替：

Customer ID	202012	202101	202102
12345	1	0	1

我做错了什么？

SELECT *
FROM
(
    SELECT CUST_ID, RULLED_PROFIT_CENTER,
      CASE WHEN PART_ID = 202012 AND ACTIVITY > 0 THEN 1 ELSE 0 END AS ARA_20,
      CASE WHEN PART_ID = 202101 AND ACTIVITY > 0 THEN 1 ELSE 0 END AS OCA_21,
      CASE WHEN PART_ID = 202102 AND ACTIVITY > 0 THEN 1 ELSE 0 END AS SUB_21,
      CASE WHEN PART_ID = 202103 AND ACTIVITY > 0 THEN 1 ELSE 0 END AS MAR_21,
      CASE WHEN PART_ID = 202104 AND ACTIVITY > 0 THEN 1 ELSE 0 END AS NIS_21,
      CASE WHEN PART_ID = 202105 AND ACTIVITY > 0 THEN 1 ELSE 0 END AS MAY_21,
      CASE WHEN PART_ID = 202106 AND ACTIVITY > 0 THEN 1 ELSE 0 END AS HAZ_21,
      CASE WHEN PART_ID = 202107 AND ACTIVITY > 0 THEN 1 ELSE 0 END AS TEM_21,
      CASE WHEN PART_ID = 202108 AND ACTIVITY > 0 THEN 1 ELSE 0 END AS AGU_21,
      CASE WHEN PART_ID = 202109 AND ACTIVITY > 0 THEN 1 ELSE 0 END AS EYL_21
    FROM ACTIVITY
    WHERE RULLED_PROFIT_CENTER IN (108, 103, 170)
    GROUP BY CUST_ID, RULLED_PROFIT_CENTER
)
WHERE ARA_20 + OCA_21 + SUB_21 + MAR_21 + NIS_21 + MAY_21 +
      HAZ_21 + TEM_21 + AGU_21 + EYL_21 > 0

Answer 1

    WHERE RULLED_PROFIT_CENTER IN (108, 103, 170)
    GROUP BY CUST_ID, RULLED_PROFIT_CENTER

您按两个值进行分组，即客户和 RULLED_PROFIT_CENTER。 RULLED_PROFIT_CENTER 可以有三个可能的值，因此每个客户最多可以获得三行。如果您只希望每个客户一行，请从您的组中删除 RULLED_PROFIT_CENTER。

您可能将 RULLED_PROFIT_CENTER 添加到组 by，因为没有它，查询将无法工作。如果您想在您的选择中包含 RULLED_PROFIT_CENTER，但不是您的分组依据，您还需要聚合 RULLED_PROFIT_CENTER。即使每个客户只有一个价值。使用string_agg。

SELECT CUST_ID, string_agg(RULLED_PROFIT_CENTER, ', ')

如果客户只有一个 RULLED_PROFIT_CENTER 值，您将只获得那个值。

---

由于您要将客户的所有行分组在一起，因此您需要获取活动的max。

MAX( CASE WHEN PART_ID = 202012 AND ACTIVITY > 0 THEN 1 ELSE 0 END ) AS ARA_20