列出 SQL 中两个日期之间的所有工作日期

Question

我有生成两个日期之间的日期列表的 SQL 代码，但我想从给定的两个日期生成工作日（工作日），

DECLARE @MinDate DATE = '20140101', @MaxDate DATE = '20140106';
SELECT TOP (DATEDIFF(DAY, @MinDate, @MaxDate) + 1)
    Date = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1,@MinDate)
FROM sys.all_objects a
CROSS JOIN sys.all_objects b;

这是我的代码，所以请任何人建议我单独获取工作日列表。 在线资源有代码来查找天数而不是列出所有日期，这是我的困惑。

Answer 1

试试这个：

DECLARE @MinDate DATE = '20140101',
        @MaxDate DATE = '20140106'

;WITH N1 (N) AS (SELECT 1 FROM (VALUES (1), (1), (1), (1), (1), (1), (1), (1), (1), (1)) n (N)),
N2 (N) AS (SELECT 1 FROM N1 AS N1 CROSS JOIN N1 AS N2),
N3 (N) AS (SELECT 1 FROM N2 AS N1 CROSS JOIN N2 AS N2),
N4 (N) AS (SELECT ROW_NUMBER() OVER(ORDER BY N1.N) FROM N3 AS N1 CROSS JOIN N3 AS N2)
SELECT  Date = DATEADD(DAY, N - 1, @MinDate)
FROM    N4
WHERE 
  N < DATEDIFF(DAY, @MinDate, @MaxDate) + 2 AND
  DATEDIFF(DAY, 1 - N, @MinDate) % 7 NOT IN (5,6)

结果：

Date
2014-01-01
2014-01-02
2014-01-03
2014-01-06

Answer 2

将原始查询设为sub-select，它会生成两个给定日期之间的所有日期，然后在outer query 中进行过滤。

SET DATEFIRST 1

select [Date] from
(
SELECT  TOP (DATEDIFF(DAY, @MinDate, @MaxDate) + 1)
    Date = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1,@MinDate)
FROM    sys.all_objects a
    CROSS JOIN sys.all_objects b
)
where datename(dw,[Date]) not in ('Saturday','Sunday')

Answer 3

DECLARE @MinDate DATE = '20140101', @MaxDate DATE = '20140106';
SELECT  TOP (DATEDIFF(DAY, @MinDate, @MaxDate) + 1)
    Date = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1,@MinDate)
FROM sys.all_objects a
CROSS JOIN sys.all_objects b
WHERE datename(dw,@MinDate) NOT IN ('Saturday','Sunday') 
      AND datename(dw,@MaxDate) NOT IN ('Saturday','Sunday') ;

Answer 4

很久以前，我建立了一个日历表来回答像你这样的问题。除了易用性之外，主要好处是您可以查看针对日历表的查询并说：“这显然正确。”

select cal_date, day_of_week
from calendar
where day_of_week in ('Mon', 'Tue', 'Wed', 'Thu', 'Fri')
  and cal_date between '2014-01-01' and '2014-01-06'
order by cal_date;

cal_date day_of_week -- 2014-01-01 周三 2014-01-02 星期四 2014-01-03 周五 2014-01-06 周一

我也有工作日的视图，所以我可以改为查询它。

select cal_date, day_of_week
from weekdays
where cal_date between '2014-01-01' and '2014-01-06'
order by cal_date;