在oracle中以周间隔和参数日期计数数据

Question

我正在尝试计算从参数开始日期到结束日期的间隔周的数据。到目前为止，我得到了这个代码：

SELECT  TRUNC(HAZARD_DATE, 'WW') week, count(*) as TOTAL 
FROM T_HAZARD a
WHERE A.HAZARD_DATE BETWEEN :parStart AND :parEnd
GROUP BY TRUNC(HAZARD_DATE, 'WW')
ORDER BY WEEK ASC

结果：

    WEEK    TOTAL
1/1/2018    181
1/8/2018    289
1/15/2018   344
1/22/2018   288

我想要的结果：

WEEK    TOTAL
 1      181
 2      289
 3      344
 4      288

感谢您的帮助..

Answer 1

你很亲密。您只需将TRUNC 函数替换为TO_CHAR（格式相同的WW）。这将返回周数，而TRUNC(..., 'WW') 返回一周第一天的日期。

SELECT TO_CHAR(HAZARD_DATE, 'WW') week, count(*) as TOTAL 
FROM T_HAZARD a
WHERE A.HAZARD_DATE BETWEEN :parStart AND :parEnd
GROUP BY TO_CHAR(HAZARD_DATE, 'WW')
ORDER BY WEEK ASC