使用查询 SQL Server 使用 3 个重复值、1 个唯一值和 1 个增量值更新表

Question

我有一个有 5 列的表。该表如下所示：

桌上的一点解释：

1. 每个Group 有6 个属性。
2. 大约有 25-30 个 groups 具有相同的属性。例如，Group 8010 与 group 8005 具有完全相同的属性。
3. 唯一的区别是，Line 每新行增加 1 列。
4. 我有 7 或 8 个不同的 groups，其中包含 25-30 个组。

这是我想要完成的任务：
我正在尝试编写一个 insert 语句来执行此操作：

1. 使用Insert 语句从一个group 获取值并将其插入下一个。
2. 使用基于先前值自动填充Line 值的函数（我查看了Rank()，但不确定是否可以在此处使用）。

我的插入语句应该是这样的：

INSERT INTO
    TableName (Group, Line, Brand, Param, Value)
VALUES
    (8010 
    ,RANK()
    ,(
        Select 
            Brand, Param, Value 
        from
            TableName
        Where 
            Group = '8005'
    )

对于下一个group，我将编写相同的查询，但将Group 的值更改为8015 等等。

我很难弄清楚 RANK() 部分和 SELECT 子查询以获取要插入的值。

任何帮助将不胜感激。谢谢

编辑 1：
这是新表的样子：

粗体部分是新数据。我正在使用 SQL Server 2012。

Answer 1

这是一个简单的方法，您只需更改@nextGroup 变量。它使用ROW_NUMBER()。

declare @table table ([Group] int, Line int, Brand char(2), [Param] varchar(64), Value varchar(256))
insert into @table values
(8005,1,'MO','CUT SPEED','55 Series'),
(8005,2,'MO','CUT BLADE','450 Series'),
(8005,3,'MO','CUT SPEED OV','60 Series'),
(8005,4,'MO','CUT BLADE OV','475 Series'),
(8005,5,'MO','CUT COMMENTS','Slow'),
(8005,6,'MO','CUT OV COMMENTS','Fast')

declare @nextGroup int = 8010
declare @currentGroup int = (select max([Group]) from @table where [Group] < @nextGroup)
declare @nextLine int = (select max([Line]) from @table where [Group] = @currentGroup)

insert into @table
    select
        @nextGroup as [Group]
        ,@nextline + row_number() over (order by (select null)) as Line
        ,t.Brand
        ,t.Param
        ,t.Value
    from @table t
    where t.[Group] = @currentGroup

set @nextGroup = 8015
set @currentGroup = (select max([Group]) from @table where [Group] < @nextGroup)
set @nextLine = (select max([Line]) from @table where [Group] = @currentGroup)

insert into @table
    select
        @nextGroup as [Group]
        ,@nextline + row_number() over (order by (select null)) as Line
        ,t.Brand
        ,t.Param
        ,t.Value
    from @table t
    where t.[Group] = @currentGroup

select * from @table

使用光标

--test data
declare @table table ([Group] int, Line int, Brand char(2), [Param] varchar(64), Value varchar(256))
insert into @table values
(8005,1,'MO','CUT SPEED','55 Series'),
(8005,2,'MO','CUT BLADE','450 Series'),
(8005,3,'MO','CUT SPEED OV','60 Series'),
(8005,4,'MO','CUT BLADE OV','475 Series'),
(8005,5,'MO','CUT COMMENTS','Slow'),
(8005,6,'MO','CUT OV COMMENTS','Fast')

--variables for handling data conditions
declare @nextGroup int 
declare @currentGroup int
declare @nextLine int

--table with all the group numbers to use
declare @groupTable table (nextGroup int)
insert into @groupTable values
(8010),
(8015),
(8020)

--cursor to loop through the set based inserts
declare groupCursor cursor fast_forward for
select nextGroup from @groupTable

open groupCursor
fetch next from groupCursor into @nextGroup

while @@FETCH_STATUS = 0
begin

    --get the last group inserted. The where condition isn't really needed
    set @currentGroup = (select max([Group]) from @table where [Group] < @nextGroup)
    --this figures out what the last line number was in the table
    set @nextLine = (select max([Line]) from @table where [Group] = @currentGroup)


    insert into @table
    select
        @nextGroup as [Group]
        --Here we increase the line number by 1 according to the last one
        ,@nextLine + row_number() over (order by (select null)) as Line
        ,t.Brand
        ,t.Param
        ,t.Value
    from @table t
    where t.[Group] = @currentGroup

    fetch next from groupCursor into @nextGroup
end

close groupCursor
deallocate groupCursor

select * from @table