如何使用lastinsertid，LAST_INSERT_ID将记录插入两个表（PHP MYSQL）[重复]

Question

我有两个表，在表 1 中，有一个自动增量 ID，我想在记录保存到表 1 后立即将最后一个 ID 插入表 2。是否可以这样做。我有一个用户填写的表格，然后在提交时将收集的数据提交到两个不同的表格。 这是我插入数据的代码

class.php

public function insertID(){
  $query = "INSERT INTO table_1 SET book_name=:book_name; INSERT INTO table_2 SET 
book_type=:book_type, book_type_id=:book_type_id";

 $stmt = $this->conn->prepare($query);

 $this->book_name=$this->name;  //this data came from a form
 $this->book_type=$this->book_type; //same as this one
 $this->book_type_id=(Im not sure what to put here)(I tried LAST_INSERT_ID and 
 mysqli_insert_id) 
 //data the will go here should come from the last inserted ID so I connect table 1 and 
 table 2 using this ID

  $stmt->bindParam(':book_name', $this->book_name);
  $stmt->bindParam(':book_type', $this->book_type);
  $stmt->bindParam(':book_type_id', $this->book_type_id);

  if($stmt->execute()){
        return  true;
    }else{
        return false;
    }
 }

这是我的表格

 include_once 'class.php';
 $class = new Class($db);

 if($_POST){
     $class->book_name=$_POST['book_name'];
     $class->book_type=$_POST['book_type'];

  if($class->insertId()){
    echo "saved";
   }else {
     not saved
    }
  }    

任何建议将不胜感激。

这是我在@GMB 的帮助下的解决方案

class.php

public function insertID(){

 $query_1 = "INSERT INTO table_1
     SET book_name=:book_name";

     $stmt_1 = $this->conn->prepare($query_1);         

     $this->book_name=$this->book_name; 

     $stmt_1->bindParam(':book_name', $this->book_name);

     if($stmt_1->execute()){

           $query_2 = "INSERT INTO table_2 
            SET book_type=:book_type, book_type_id=:book_type_id";

            $stmt_2 = $this->conn->prepare($query_2);

            $this->book_type=$this->book_type;
            $this->book_type_id=$this->conn->lastInsertId();

            $stmt_2->bindParam(':book_type', $this->book_type);
            $stmt_2->bindParam(':book_type_id', $this->book_type_id);

                  if($stmt_2->execute()){
                     return  true;
                         }else{
                           return false;
                                 }
    }else{
        return false;
    }
 }

Answer 1

您可以使用两个单独的查询来做到这一点：

$query1 = "INSERT INTO table_1(book_name) VALUES(:book_name)";
$query2 = "INSERT INTO table_2(book_type, book_type_id) VALUES(:book_type, LAST_INSERT_ID())";

第一个查询插入到父表中。秒使用MySQL函数LAST_INSERT_ID()恢复上一次插入时生成的id，插入到子表中。

您需要在单独的数据库调用中独立运行每个查询。比如：

$query1 = "INSERT INTO table_1(book_name) VALUES(:book_name)";
$stmt1 = $this->conn->prepare($query1);
$stmt1->bindParam(':book_name', ...);
if(!$stmt1->execute()){ # error handling}

$query2 = "INSERT INTO table_2(book_type, book_type_id) VALUES(:book_type, LAST_INSERT_ID())";
$stmt2 = $this->conn->prepare($query2);
$stmt1->bindParam(':book_type', ...);
if(!$stmt1->execute()){ # error handling }