SOAPpy - 如何传递安全标头？答案

【问题标题】：SOAPpy - how to pass a security Header?SOAPpy - 如何传递安全标头？
【发布时间】：2011-06-10 02:37:15
【问题描述】：

我目前正在为使用 Axis2 WS-Security 的应用程序开发一个 python web 服务

简化的相关代码为

from SOAPpy import SOAPProxy
from SOAPpy import WSDL

file = 'path/to/my/file?wsdl'
server = WSDL.Proxy(file)

server.foo(bar)

当我这样做时：

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Python27\lib\site-packages\SOAPpy\Client.py", line 471, in __call__
    return self.__r_call(*args, **kw)
  File "C:\Python27\lib\site-packages\SOAPpy\Client.py", line 493, in __r_call
    self.__hd, self.__ma)
  File "C:\Python27\lib\site-packages\SOAPpy\Client.py", line 407, in __call
    raise p
SOAPpy.Types.faultType: <Fault soapenv:Client: WSDoAllReceiver: Incoming message
 does not contain required Security header: >

阅读axis2 WS-security的文档和提供Web服务的应用程序我猜它要求我进行用户令牌身份验证

<wsse:Security xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" soapenv:mustUnderstand="1">
<wsu:Timestamp xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="Timestamp-12468716">
<wsu:Created>
2008-06-23T13:17:13.841Z
</wsu:Created>
<wsu:Expires>
2008-06-23T13:22:13.841Z
</wsu:Expires>
</wsu:Timestamp>
<wsse:UsernameToken xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="UsernameToken-31571602">
<wsse:Username>
alice
</wsse:Username>
<wsse:Password Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText">
bobPW
</wsse:Password>
</wsse:UsernameToken>
</wsse:Security>

在发出请求时，问：如何将其附加到 SOAPpy 请求中？

【问题讨论】：

标签： python web-services axis2 webservice-client soappy

【解决方案1】：

查看有关向肥皂请求添加标头的文档 (https://svn.origo.ethz.ch/playmobil/trunk/contrib/pywebsvcs/SOAPpy/docs/UsingHeaders.txt)。这样您就可以将自己的自定义标头添加到任何请求中。

希望对你有帮助

【讨论】：