【问题标题】:SQL join to next available date if date is not valid如果日期无效,SQL 连接到下一个可用日期
【发布时间】:2018-04-11 10:08:42
【问题描述】:

寻求有关查询的帮助。我有一个客户表记录链接到一个基本位置的客户。以及详细说明特定时间点的位置地址的位置表。

CREATE TABLE [dbo].[Customer](
   [ID] [int] NULL,
   [Date of Transfer] [datetime] NULL,
   [Old Location] [int] NULL,
   [New Location] [int] NULL)


INSERT INTO [dbo].[Customer] (ID, [Date of Transfer], [Old Location], [New Location])
VALUES  (1, '2016-07-01 00:00:00.000', 1001, 2200),
        (1, '2017-11-25 00:00:00.000', 2200, 3078),
        (1, '2018-01-01 00:00:00.000', 3078, 8500),
        (2, '2016-02-27 00:00:00.000', 5578, 9901),
        (2, '2017-06-22 00:00:00.000', 9901, 9001);

CREATE TABLE [dbo].[Location](
    [Location Code] [int] NULL,
    [Location Address] [nvarchar](50) NULL,
    [Date From] [date] NULL,
    [Date To] [date] NULL)


INSERT INTO [dbo].[Location] ([Location Code], [Location Address], [Date From], [Date To])
VALUES (1001, 'Logan Street', '1998-02-01 00:00:00.000', '2017-07-21 00:00:00.000'),
    (2200, 'Ashdown Avenue', '2014-01-31 00:00:00.000', NULL),
    (3078, 'Chessington Court', '2009-05-11 00:00:00.000', '2018-03-30 00:00:00.000'),
    (8500, 'Cambridge Green', '2018-01-15 00:00:00.000', '2018-02-15 00:00:00.000'),
    (8500, 'Blair Road', '2018-02-15 00:00:00.000', NULL),
    (5578, 'Aberdeen View', '2000-11-19 00:00:00.000', '2017-05-13 00:00:00.000'),
    (9901, 'Tay Road', '2013-02-02 00:00:00.000', '2018-01-22 00:00:00.000'),
    (9001, 'Wellington Way', '2015-02-16 00:00:00.000', '2018-02-22 00:00:00.000');

我正在尝试加入这两个表,以向我提供链接到客户的位置地址,即他们转移到另一个位置的点。这适用于大多数使用以下内容的人

SELECT [ID]
  ,[Date of Transfer]
  ,[Old Location]
  ,O.[Location Address]
  ,O.[Date From]
  ,O.[Date To]
  ,[New Location]
  ,N.[Location Address]
  ,N.[Date From]
  ,N.[Date To]
FROM [dbo].[Customer]
Left Join [dbo].[Location] O on [Old Location] = O.[Location Code] and ([Date of Transfer] >= O.[Date From] OR O.[Date From] is NULL)  and ([Date of Transfer] <= O.[Date To] or O.[Date To] is NULL)
Left Join [dbo].[Location] N on [New Location] = N.[Location Code] and ([Date of Transfer] >= N.[Date From] OR N.[Date From] is NULL)  and ([Date of Transfer] <= N.[Date To] or N.[Date To] is NULL)
ORDER BY [ID], [Date of Transfer] ASC

我遇到的问题是位置表有时更新较晚,因此客户转移不会加入任何有效位置。我想添加一个检查位置有效日期的子句。所以在我上面的例子中,我想将客户 1 的转账到 8500 链接到转账后 1 个月左右更新的 Cambridge Green 地址。有谁知道我该怎么做。

当前示例输出

ID          Date of Transfer        Old Location Location Address                                   Date From  Date To    New Location Location Address                                   Date From  Date To
----------- ----------------------- ------------ -------------------------------------------------- ---------- ---------- ------------ -------------------------------------------------- ---------- ----------
1           2016-07-01 00:00:00.000 1001         Logan Street                                       1998-02-01 2017-07-21 2200         Ashdown Avenue                                     2014-01-31 NULL
1           2017-11-25 00:00:00.000 2200         Ashdown Avenue                                     2014-01-31 NULL       3078         Chessington Court                                  2009-05-11 2018-03-30
1           2018-01-01 00:00:00.000 3078         Chessington Court                                  2009-05-11 2018-03-30 8500         NULL                                               NULL       NULL
2           2016-02-27 00:00:00.000 5578         Aberdeen View                                      2000-11-19 2017-05-13 9901         Tay Road                                           2013-02-02 2018-01-22
2           2017-06-22 00:00:00.000 9901         Tay Road                                           2013-02-02 2018-01-22 9001         Wellington Way                                     2015-02-16 2018-02-22

客户 1 的最后一行尚未链接到位置,因为在转移期间没有列出任何位置。因此,我想检查自转移日期以来该位置代码的下一个位置地址是什么。

注意:位置表的每个位置可以有多个地址(在不同时期。因此我不能使用简单的连接。

期望的输出。

ID          Date of Transfer        Old Location Location Address                                   Date From  Date To    New Location Location Address                                   Date From  Date To
----------- ----------------------- ------------ -------------------------------------------------- ---------- ---------- ------------ -------------------------------------------------- ---------- ----------
1           2016-07-01 00:00:00.000 1001         Logan Street                                       1998-02-01 2017-07-21 2200         Ashdown Avenue                                     2014-01-31 NULL
1           2017-11-25 00:00:00.000 2200         Ashdown Avenue                                     2014-01-31 NULL       3078         Chessington Court                                  2009-05-11 2018-03-30
1           2018-01-01 00:00:00.000 3078         Chessington Court                                  2009-05-11 2018-03-30 8500         Cambridge Green                                    2018-01-15 2018-02-15
2           2016-02-27 00:00:00.000 5578         Aberdeen View                                      2000-11-19 2017-05-13 9901         Tay Road                                           2013-02-02 2018-01-22
2           2017-06-22 00:00:00.000 9901         Tay Road                                           2013-02-02 2018-01-22 9001         Wellington Way                                     2015-02-16 2018-02-22

【问题讨论】:

  • 您能否发布表中数据的实际和预期输出?

标签: sql join sql-server-2016


【解决方案1】:

试试这个。

SELECT [ID]
  ,[Date of Transfer]
  ,[Old Location]
  ,O.[Location Address]
  ,O.[Date From]
  ,O.[Date To]
  ,[New Location]
  ,N.[Location Address]
  ,N.[Date From]
  ,N.[Date To]
FROM [dbo].[Customer]
Left Join [dbo].[Location] O on [Old Location] = O.[Location Code] and ([Date of Transfer] >= O.[Date From] OR O.[Date From] is NULL)  and ([Date of Transfer] <= O.[Date To] or O.[Date To] is NULL)
Left Join [dbo].[Location] N on [New Location] = N.[Location Code] and ([Date of Transfer] >= N.[Date From] OR N.[Date From] is NULL or N.[Date To] is NULL)  and ([Date of Transfer] <= N.[Date To] or N.[Date To] is NULL)
ORDER BY [ID], [Date of Transfer] ASC

【讨论】:

  • 再次感谢,但您可能误解了我的问题。我需要加入两个日期之间的值。如果现在值在两个日期之间匹配,则我需要查找转移日期之后日期最近的位置。
【解决方案2】:

试试这个。

SELECT [ID]
  ,[Date of Transfer]
  ,[Old Location]
  ,O.[Location Address]
  ,O.[Date From]
  ,O.[Date To]
  ,[New Location]
  ,N.[Location Address]
  ,N.[Date From]
  ,N.[Date To]
FROM [dbo].[Customer]
Left Join [dbo].[Location] O on [Old Location] = O.[Location Code] and ([Date of Transfer] >= O.[Date From] OR O.[Date From] is NULL)  and ([Date of Transfer] <= O.[Date To] or O.[Date To] is NULL)
Join [dbo].[Location] N on [New Location] = N.[Location Code] and ([Date of Transfer] >= N.[Date From] OR N.[Date From] is NULL)  and ([Date of Transfer] <= N.[Date To] or N.[Date To] is NULL)
ORDER BY [ID], [Date of Transfer] ASC

【讨论】:

  • 谢谢,但这并没有考虑到具有该代码的另一个位置也可能包含在具有不同地址的表中。
  • 你能把你想要的输出分享给完整的案例吗?
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