【发布时间】:2019-05-21 20:33:57
【问题描述】:
该函数应在当前日期之后返回一个新日期,并添加 num_of_flows。 num_of_flows 是一个整数值
ALTER function [dbo].[M20_22_GetLoanMaturityDate_FIN_10]
(
@AcctAcid varchar(50),
@ScheduleNum varchar(50),
@bank_id varchar(6) = '03'
)
returns varchar(50)
as
BEGIN
Declare @lMaturityDate varchar(50)
begin
select @lMaturityDate =
case Finacle_Lrs.LR_FREQ_TYPE
when 'W' then dateadd(day, (Finacle_Lrs.NUM_OF_FLOWS - 1) * 7,Finacle_Lrs.FLOW_START_DATE)
when 'F' then dateadd(day, (Finacle_Lrs.NUM_OF_FLOWS - 1) * 14,Finacle_Lrs.FLOW_START_DATE)
when 'M' then (dateadd(month, Finacle_Lrs.NUM_OF_FLOWS - 1, Finacle_Lrs.FLOW_START_DATE))
when 'Q' then (dateadd(month, (Finacle_Lrs.NUM_OF_FLOWS - 1) * 3, Finacle_Lrs.FLOW_START_DATE))
when 'H' then dateadd(month, (Finacle_Lrs.NUM_OF_FLOWS - 1) * 6, Finacle_Lrs.FLOW_START_DATE)
when 'Y' then dateadd(month, (Finacle_Lrs.NUM_OF_FLOWS - 1) * 12, Finacle_Lrs.FLOW_START_DATE)
end
from [TEST_EIMDW_Archive].[ARCHOWN].[FINCL10_LRS] Finacle_Lrs
where Finacle_Lrs.acid = @AcctAcid
and Finacle_Lrs.shdl_num = @ScheduleNum
and Finacle_Lrs.FLOW_ID in ('PRDEM','EIDEM')
AND Finacle_Lrs.ACTIVE_FLAG = 'Y' AND Finacle_Lrs.DELETE_FLAG= 'N'
and Finacle_Lrs.bank_id = @bank_id
and Finacle_Lrs.FLOW_START_DATE = ( select max(a.FLOW_START_DATE)
from [TEST_EIMDW_Archive].[ARCHOWN].[FINCL10_LRS] a
where a.ACID = Finacle_Lrs.ACID
and a.SHDL_NUM = Finacle_Lrs.SHDL_NUM
and a.FLOW_ID in ('PRDEM', 'EIDEM') AND a.ACTIVE_FLAG = 'Y' AND a.DELETE_FLAG='N' and a.bank_id = @bank_id
);
end
return isnull(@lMaturityDate,null);
END
在做了一些检查之后,我注意到有一天在比较 oracle 数据库上的原始代码时,altest 低估了 19629 行。请看oracle版本的代码:
FUNCTION GetLoanMaturityDate(AcctAcid VARCHAR2, ScheduleNum VARCHAR2) RETURN DATE IS
lMaturityDate DATE;
BEGIN
begin
select decode(lrs.LR_FREQ_TYPE, 'W', lrs.FLOW_START_DATE + (lrs.NUM_OF_FLOWS - 1) * 7,
'F', lrs.FLOW_START_DATE + (lrs.NUM_OF_FLOWS - 1) * 14,
'M', add_months(lrs.FLOW_START_DATE, lrs.NUM_OF_FLOWS - 1) ,
'Q', add_months(lrs.FLOW_START_DATE, (lrs.NUM_OF_FLOWS - 1) * 3),
'H', add_months(lrs.FLOW_START_DATE, (lrs.NUM_OF_FLOWS - 1) * 6),
'Y', add_months(lrs.FLOW_START_DATE, (lrs.NUM_OF_FLOWS - 1) * 12)
)
into lMaturityDate
from lrs
where lrs.acid = AcctAcid
and lrs.shdl_num = ScheduleNum
and lrs.FLOW_ID in ('PRDEM','EIDEM')
and lrs.FLOW_START_DATE = ( select max(a.FLOW_START_DATE)
from lrs a
where a.ACID = lrs.ACID
and a.SHDL_NUM = lrs.SHDL_NUM
and a.FLOW_ID in ('PRDEM', 'EIDEM')
) ;
exception
when no_data_found then
lMaturityDate:=NULL;
end;
return lMaturityDate;
END GetLoanMaturityDate;
这也是我运行的比较查询以查看不正确的行:
SELECT eim.acid as eim_acid,it.[ACID] as it_acid,
eim.[MATURITY_DATE] as eim_maturity_date,it.[MATURITY_DATE] as it_maturity_date ,
eim.[DAYS_TO_MATURITY] as eim_DAYS_TO_MATURITY,it.[DAYS_TO_MATURITY] as it_DAYS_TO_MATURITY,(it.[DAYS_TO_MATURITY]-eim.[DAYS_TO_MATURITY]) as diff
FROM [TEST_EIMDW_BOJ_REPORTS].[BOJOWN].[loans_maturity_profile] eim
inner join [dbo].[IT_LOANS_MATURITY_PROFILE] it on eim.acid= it.acid
where eim.MATURITY_DATE != it.MATURITY_DATE
最后,下面的查询结果显示了正确结果集与我目前尝试在 sql server 上修复的结果集的比较:
【问题讨论】:
-
这里要小心。您正在计算一个日期,然后返回一个 varchar。您应该返回日期而不是字符串。此外,sql server 中的标量函数的性能也是出了名的差。如果有很多操作,转换为内联表值函数可能是个好主意。
-
@SeanLange 指出,但是,我正在寻找一种在 sql server 中重现 Oracle 代码的方法。有什么想法吗?
-
我对甲骨文并不精通,并且承认戈登在该领域的知识比我所拥有的要好得多。请看下面他的回答。可能不是你想听到的。
-
看起来他总是需要每月的最后一天。使用“月末”(EOMONTH ( start_date [, month_to_add ] ) )函数会在这里产生更好的结果。
标签: sql sql-server oracle tsql