在 XML Path 中组合同一级别的字段答案

【问题标题】：Combining fields at the same level in XML Path在 XML Path 中组合同一级别的字段
【发布时间】：2014-01-21 15:16:10
【问题描述】：

我正在尝试将以下 XML 生成为表格的一列：

<root>
    <Address1>
        <Addressline1>Test Road</Addressline1>
        <Addressline2>Test Street</Addressline2>
        <Addressline3>Test Town</Addressline3>
        <Addressline4>Test State</Addressline4>
        <Postcode>Test Postcode</Postcode>
    </Address1>
    <Address2>
        <Addressline1>Test Road</Addressline1>
        <Addressline2>Test Street</Addressline2>
        <Addressline3>Test Town</Addressline3>
        <Addressline4>Test State</Addressline4>
        <Postcode>Test Postcode</Postcode>
    </Address2>
</root>

下面的 SQL 差不多了：

select  (1Addressline1,
        1Addressline2,
        1Addressline3,
        1Addressline4,
        1Postcode for xml path('Address'), root('Addresses')) AS Address1,
        (2Addressline1,
        2Addressline2,
        2Addressline3,
        2Addressline4,
        2Postcode for xml path('Address'), root('Addresses')) AS Address2,
        ColumnA
        ColumnB
        ColumnC
From    Addresses

生成以下 XML：

<root>
    <Address1>
        <Addressline1>Test Road</Addressline1>
        <Addressline2>Test Street</Addressline2>
        <Addressline3>Test Town</Addressline3>
        <Addressline4>Test State</Addressline4>
        <Postcode>Test Postcode</Postcode>
    </Address1>
</root>,    
<root>
    <Address2>
        <Addressline1>Test Road</Addressline1>
        <Addressline2>Test Street</Addressline2>
        <Addressline3>Test Town</Addressline3>
        <Addressline4>Test State</Addressline4>
        <Postcode>Test Postcode</Postcode>
    </Address2>
</root>,    
ColumnA,
ColumnB,
ColumnC

生成两个单独的 XML 列是不正确的。我现在需要像上面那样在根节点下组合地址 1 和地址 2，但无法解决或找到正确的语法。

编辑：正如我所建议的，我已将我的代码修改为此给出了一些语法错误：

SELECT      ColumnA,
            ColumnB,
            ColumnC,

            (
                select
                (
                    (
                        select      RTRIM(Address1Line1),
                                    RTRIM(Address1Line2),
                                    RTRIM(Address1Line3),
                                    RTRIM(Address1Line4),
                                    RTRIM(Address1Line5) 
                        for xml path('Address'), type
                    ),
                    (
                        select      RTRIM(Address2Line1),
                                    RTRIM(Address2Line2),
                                    RTRIM(Address2Line3),
                                    RTRIM(Address2Line4),
                                    RTRIM(Address2Line5)
                        for xml path('Address'), type
                    )
                ) FOR XML PATH(''), root('Addresses'),type
            ) AS Addresses

FROM        TableA

【问题讨论】：

标签： sql sql-server for-xml-path

【解决方案1】：

DECLARE @Addresses TABLE 
(AddressNumber INT, Addressline1 VARCHAR(50),Addressline2 VARCHAR(50)
,Addressline3 VARCHAR(50),Addressline4 VARCHAR(50),PostCode VARCHAR(50))

INSERT INTO @Addresses VALUES 
(1,'Add 1 Addressline1', 'Add 1 Addressline2', 'Add 1 Addressline3', 'Add 1 Addressline4', 'ABCD132'),
(2,'Add 2 Addressline1', 'Add 2 Addressline2', 'Add 2 Addressline3', 'Add 2 Addressline4', 'JKLM132'),
(3,'Add 3 Addressline1', 'Add 3 Addressline2', 'Add 3 Addressline3', 'Add 3 Addressline4', 'RTPZ132'),
(4,'Add 4 Addressline1', 'Add 4 Addressline2', 'Add 4 Addressline3', 'Add 4 Addressline4', 'XMLO132')


select   AddressNumber [@AddressID]
        ,Addressline1
        ,Addressline2
        ,Addressline3
        ,Addressline4
        ,PostCode
FROM    @Addresses 
for xml PATH('Address'),Elements , root('PatientAddress')

结果集

<PatientAddress>
  <Address AddressID="1">
    <Addressline1>Add 1 Addressline1</Addressline1>
    <Addressline2>Add 1 Addressline2</Addressline2>
    <Addressline3>Add 1 Addressline3</Addressline3>
    <Addressline4>Add 1 Addressline4</Addressline4>
    <PostCode>ABCD132</PostCode>
  </Address>
  <Address AddressID="2">
    <Addressline1>Add 2 Addressline1</Addressline1>
    <Addressline2>Add 2 Addressline2</Addressline2>
    <Addressline3>Add 2 Addressline3</Addressline3>
    <Addressline4>Add 2 Addressline4</Addressline4>
    <PostCode>JKLM132</PostCode>
  </Address>
  <Address AddressID="3">
    <Addressline1>Add 3 Addressline1</Addressline1>
    <Addressline2>Add 3 Addressline2</Addressline2>
    <Addressline3>Add 3 Addressline3</Addressline3>
    <Addressline4>Add 3 Addressline4</Addressline4>
    <PostCode>RTPZ132</PostCode>
  </Address>
  <Address AddressID="4">
    <Addressline1>Add 4 Addressline1</Addressline1>
    <Addressline2>Add 4 Addressline2</Addressline2>
    <Addressline3>Add 4 Addressline3</Addressline3>
    <Addressline4>Add 4 Addressline4</Addressline4>
    <PostCode>XMLO132</PostCode>
  </Address>
</PatientAddress>

【讨论】：

这就是我想要的。问题是表有两组地址列：

【解决方案2】：

只需将文字替换为表中列的名称即可：

select
(SELECT '1' addressline1,'2' addressline2, '3' addressline3, '4' addressline4, 'PC' postcode for xml path('Address1'), type ),
(SELECT '21' addressline1,'22' addressline2, '23' addressline3, '24' addressline4, '2PC' postcode for xml path('Address2'), type  )
FOR XML PATH(''), root('PatientAddress'),type

【讨论】：