如何解决“Readonly<{}> 类型上不存在属性“导航”&

Question

我有以下两段代码：

CustomHeader.tsx

import { View, StyleSheet, Button } from 'react-native';
import { NavigationScreenProps } from 'react-navigation';
import Icon from 'react-native-vector-icons/Ionicons';


export  const CustomHeader = ({ navigation }: NavigationScreenProps) => (
    <View style={[styles.container]}>
      <Icon
        name="md-menu"
        size={32}
        color="black"
        style={{ marginLeft: 10 }}
        onPress={() => navigation.openDrawer()}
      />
    </View>
  );

  const styles = StyleSheet.create({
    container: {
      borderBottomWidth: 2,
      height: 70,
      paddingTop: 20,
    },
  });

DetailScreen.tsx

import React from 'react';
import { Text, View, Button, Alert } from 'react-native';
import { NavigationScreenProps } from "react-navigation";
import { CustomHeader } from '../components/Header';

export class ChangeAccountDetailScreen extends React.Component {
  render() {
    return (
      <View style={{ flex: 1 }}>
        <CustomHeader navigation={this.props.navigation} />
        <Text style={{ fontSize: 20 }}>Profile Screen</Text>
      </View>
    );
  }
}

在detailscreen中我收到以下错误：

类型'Readonly & Readonly'。

我搜索了这个问题，我知道它有一些事实，即我没有在我的 CustomHeader 中声明类型。但是我不知道如何解决这个问题。我对打字稿有点陌生。有人可以向我解释如何解决这种类型的问题吗？

Answer 1

import React from 'react';
import { Button } from 'react-native';
import { withNavigation } from 'react-navigation';

class MyBackButton extends React.Component {
  render() {
    return <Button title="Back" onPress={() => { this.props.navigation.goBack() }} />;
  }
}

// withNavigation returns a component that wraps MyBackButton and passes in the
// navigation prop
export default withNavigation(MyBackButton);

https://reactnavigation.org/docs/en/connecting-navigation-prop.html

Answer 2

我可能是错的，但是您是否尝试过添加 navigation 类型来预期

import React from 'react';
import { Text, View, Button, Alert } from 'react-native';
import { NavigationScreenProps } from "react-navigation";
import { CustomHeader } from '../components/Header';

interface Props {
  navigation: any
}

export class ChangeAccountDetailScreen extends React.Component<Props> {
  render() {
    return (
      <View style={{ flex: 1 }}>
        <CustomHeader navigation={this.props.navigation} />
        <Text style={{ fontSize: 20 }}>Profile Screen</Text>
      </View>
    );
  }
}

Answer 3

这是另一个解决方案，我在接口定义中添加了更多细节

import React from 'react';
import { Text, View, Button, Alert } from 'react-native';
import {
  NavigationParams,
  NavigationScreenProp,
  NavigationState
} from 'react-navigation';
import { CustomHeader } from '../components/Header';

interface Props {
  navigation: NavigationScreenProp<NavigationState, NavigationParams>
}

export class ChangeAccountDetailScreen extends React.Component<Props> {
  render() {
    return (
      <View style={{ flex: 1 }}>
        <CustomHeader navigation={this.props.navigation} />
        <Text style={{ fontSize: 20 }}>Profile Screen</Text>
      </View>
    );
  }
}

Answer 4

更现代的答案是使用useNavigation，如https://reactnavigation.org/docs/connecting-navigation-prop/ 中所述

import * as React from 'react';
import { Button } from 'react-native';
import { useNavigation } from '@react-navigation/native';

function GoToButton({ screenName }) {
  const navigation = useNavigation();

  return (
    <Button
      title={`Go to ${screenName}`}
      onPress={() => navigation.navigate(screenName)}
    />
  );
}

Answer 5

解决这个问题的另一种方法是从 react 中导入 ReactNode，并告诉组件它的类型为 ReactNode。

import React,{ReactNode} from 'react'

const GetStarted:ReactNode = ({navigation})=>{
return(
   <View> </View>
)
}