首先按布尔列对数组进行排序，然后按字符串列排序

Question

我正在尝试按 2 个字段对数组进行排序。我有一个布尔值：isFavorite 和一个字符串：名称。 所有为真的布尔值都必须是第一项。但我希望数组按字母顺序排列。这是我到目前为止的代码（尝试了多种方法）：

data.sort(function (x,y) {
    if (x.isFavorite){
        return -1;
    }
    if (x.isFavorite && !y.isFavorite && (x.name < y.name)){
        return -1;
    }  else if ((x.isFavorite === y.isFavorite) && (x.name === y.name)){
        return 0;
    } else if (x.isFavorite && y.isFavorite && (x.name < y.name)){
        return -1;
    } else if (!x.isFavorite && !y.isFavorite && (x.name > y.name)){
        return 1;
    }
}

Answer 1

您的问题是前两个if 重叠，如果x.isFavorite 是true，则第二个if 不可达，那么第一个if 将return。

此外，您没有检查某些情况，例如 y.isFavorite 是 true 而 x.isFavorite 不是。

你可以写成

if ( x.isFavorite != y.isFavorite )
{
   return x.isFavorite ? -1 : 1;
}
else
{
   return x.name.localeCompare( y.name );
}

Answer 2

为什么会有这么多条件和重叠？

只需使用logical OR 运算符即可按两个字段对数组进行排序。

另外，我使用+ (Boolean) 来强制转换为数字。

grouperArray.sort((a, b) => (+a.isFavorite) - (+b.isFavorite) || a.name.localeCompare(b.name));

let data = [{ isFavorite:false, name:'A' }, { isFavorite:true, name:'C' }, { isFavorite:true, name:'B' }];
data.sort((a,b) => (+b.isFavorite) - (+a.isFavorite) || a.name.localeCompare(b.name));
console.log(data);

Answer 3

给你:)

var arr = [
  {
    isFavorite: false,
    name: 'a'
  },
  {
    isFavorite: true,
    name: 'b'
  },
  {
    isFavorite: true,
    name: 'c'
  },
  {
    isFavorite: false,
    name: 'c'
  }
];

arr.sort(function (x,y) {
    if (x.isFavorite > y.isFavorite){
        return -1;
    }else if(x.isFavorite == y.isFavorite){
        return x.name > y.name;
    }else{
        return 1;
    }
});

console.log(arr);

Answer 4

const data = [
  {isFavorite: false, name: 'b'},
  {isFavorite: false, name: 'f'},
  {isFavorite: true, name: 'c'},
  {isFavorite: true, name: 'a'},
  {isFavorite: false, name: 'd'},
  {isFavorite: true, name: 'g'}
];

const sortedData = data.sort((a, b) => {
  if (a.isFavorite !== b.isFavorite) {
    return a.isFavorite ? -1 : 1;
  } else {
    return a.name > b.name ? 1 : -1;
  }
});
  
console.log(sortedData);

Answer 5

试试这个：

const data = [
  {isFavorite: false, name: 'B'}, 
  {isFavorite: false, name: 'A'}, 
  {isFavorite: true, name: 'C'}, 
  {isFavorite: true, name: 'D'},
  {isFavorite: true, name: 'A'},
  {isFavorite: false, name: 'A'},
  {isFavorite: false, name: 'D'},
  {isFavorite: true, name: 'Z'},
];

const compareLoc = (a, b) => a.name.localeCompare(b.name)
const result = [...data.filter(d => d.isFavorite).sort(compareLoc),
...data.filter(d => !d.isFavorite).sort(compareLoc)];
console.log(result);

以下 sn-p 作品。

const data = [
  {isFavorite: false, name: 'B'}, 
  {isFavorite: false, name: 'A'}, 
  {isFavorite: true, name: 'C'}, 
  {isFavorite: true, name: 'D'},
  {isFavorite: true, name: 'A'},
  {isFavorite: false, name: 'A'},
  {isFavorite: false, name: 'D'},
  {isFavorite: true, name: 'Z'},
];

data.sort(function (x, y) {
    // if both are true or false, we should compare name attributes
    if (x.isFavorite === y.isFavorite) {
        return x.name.localeCompare(y.name);
    } return x.isFavorite ? -1 : 1
}
)
console.log(data)