在打字稿中向对象数组插入新值

Question

我们如何在 typescript 中向对象数组插入值？

我想将 1993 年的值插入到示例对象上的每个年度租金当前值。

所以每个年度租金当前值现在都是 1993 年。有什么想法吗？ .我们如何在 typescript 或 angular 中解决这个问题？谢谢。

#我要插入的数据

this.transaction.propertyDto.propertyDetailDto.annualRentUsd = 1993;

#示例对象

   this.data.object = [
        {
            "id": 196,
            "name": "Partner Deal ",
            "dealType": "Partner Location Submission",
            "annualRentProposed": null,
            "annualRentCurrent": null,
            "firmTermRemaining": null,
            "firmTermAdded": null,
            "maxAvailableTerm": null,
            "capitalContribution": null,
            "createdOnString": "09/30/2021",
            "fileName": null,
            "serverFileName": null,
            "size": null,
            "absoluteUri": null,
            "sentTo": null
        },
        {
            "id": 197,
            "name": "Buyout Deal Disposition",
            "dealType": "Idle Buyout",
            "annualRentProposed": null,
            "annualRentCurrent": null,
            "firmTermRemaining": null,
            "firmTermAdded": null,
            "maxAvailableTerm": null,
            "capitalContribution": null,
            "createdOnString": "09/30/2021",
            "fileName": null,
            "serverFileName": null,
            "size": null,
            "absoluteUri": null,
            "sentTo": null
        },
        {
            "id": 199,
            "name": "Sublease Deal Disposition",
            "dealType": "Idle Sublease",
            "annualRentProposed": null,
            "annualRentCurrent": null,
            "firmTermRemaining": null,
            "firmTermAdded": null,
            "maxAvailableTerm": null,
            "capitalContribution": null,
            "createdOnString": "09/30/2021",
            "fileName": null,
            "serverFileName": null,
            "size": null,
            "absoluteUri": null,
            "sentTo": null
        },
        {
            "id": 203,
            "name": "Disposition of Location #10532-S",
            "dealType": "PM Restructure",
            "annualRentProposed": null,
            "annualRentCurrent": null,
            "firmTermRemaining": null,
            "firmTermAdded": null,
            "maxAvailableTerm": null,
            "capitalContribution": null,
            "createdOnString": "10/01/2021",
            "fileName": null,
            "serverFileName": null,
            "size": null,
            "absoluteUri": null,
            "sentTo": null
        },
        {
            "id": 214,
            "name": null,
            "dealType": "Approval to Close",
            "annualRentProposed": null,
            "annualRentCurrent": null,
            "firmTermRemaining": null,
            "firmTermAdded": null,
            "maxAvailableTerm": null,
            "capitalContribution": null,
            "createdOnString": "10/04/2021",
            "fileName": null,
            "serverFileName": null,
            "size": null,
            "absoluteUri": null,
            "sentTo": null
        },
        {
            "id": 215,
            "name": "pmpm",
            "dealType": "PM Restructure",
            "annualRentProposed": null,
            "annualRentCurrent": null,
            "firmTermRemaining": null,
            "firmTermAdded": null,
            "maxAvailableTerm": null,
            "capitalContribution": null,
            "createdOnString": "10/05/2021",
            "fileName": null,
            "serverFileName": null,
            "size": null,
            "absoluteUri": null,
            "sentTo": null
        }
    ]

Answer 1

由于您只想为数组中的所有元素设置相同的值，您可以使用map：

this.data.object.map(o => o.annualRentCurrent = 1993);

或forEach:

this.data.object.forEach(o => o.annualRentCurrent = 1993);

在这种情况下它们基本上是相同的，但map 将返回一个新数组（在这种情况下也会改变原始数组），而 forEach 只是迭代原始数组中的每个元素。