【发布时间】:2015-01-31 01:22:30
【问题描述】:
我正在尝试实现 Hartl 的 RoR 教程第 12 章中的追随者功能。
我有一个功能,我可以登录,转到另一个用户个人资料,单击关注,(刷新页面后)我看到我现在正在关注他们。与取消关注相同。
但是,我的集成测试失败,Ajax 无法工作,当我单击关注或取消关注时,我的 Rails 服务器日志中出现此错误:
Rendered users/_follow.html.erb (1.7ms)
Rendered relationships/destroy.js.erb (2.5ms)
Completed 500 Internal Server Error in 17ms
NoMethodError - undefined method `id' for nil:NilClass:
我的代码完全符合 Hartl 的(我认为)。但是,我在我的用户模型和设计上使用 FriendlyID,其中之一(可能是 FriendlyID)会导致问题。
我相信这是所有相关的代码。
任何想法都将不胜感激......现在在第 5 小时左右!
controllers/users_controller.rb
def following
@title = "Following"
@user = User.friendly.find(params[:id])
@users = @user.following
render 'show_follow'
end
def followers
@title = "Followers"
@user = User.friendly.find(params[:id])
@users = @user.followers
render 'show_follow'
end
controllers/relationships_controller.rb
def create
user = User.friendly.find(params[:followed_id])
current_user.follow(user)
respond_to do |format|
format.html { redirect_to @user }
format.js
end
end
def destroy
user = Relationship.find(params[:id]).followed
current_user.unfollow(user)
respond_to do |format|
format.html { redirect_to @user }
format.js
end
end
models/user.rb
# follows a user
def follow(other_user)
active_relationships.create(followed_id: other_user.id)
end
# unfollows a user
def unfollow(other_user)
active_relationships.find_by(followed_id: other_user.id).destroy
end
# returns true if user is following the other user
def following?(other_user)
following.include?(other_user)
end
_unfollow.html.erb
<%= form_for(current_user.active_relationships.find_by(followed_id: @user.id),
html: { method: :delete }, remote: true) do |f| %>
<%= f.submit "Unfollow", class: "btn" %>
<% end %>
_follow.html.erb
<%= form_for(current_user.active_relationships.build(followed_id: @user.id), remote: true) do |f| %>
<div><%= hidden_field_tag :followed_id, @user.id %></div>
<%= f.submit "Follow", class: "btn" %>
<% end %>
【问题讨论】:
-
仅仅看一眼,你是否已经将@user 传递给你的关注/取消关注视图并不明显?因此,如果您的
id方法不知道@user,它将是未定义的
标签: ruby-on-rails ruby-on-rails-3 devise friendly-id