【发布时间】:2013-04-05 16:56:07
【问题描述】:
我有 3 个非常大的表,每分钟记录一次值, 以下是这些表格的摘录。
我想获得这些表的1 天期间的每小时平均值,并根据时间加入它们,请注意 ph 和温度的记录时间之间有几秒钟的差距
表 PH(仅提取,此表非常大,包含超过 130,000 个值)
ID time Ph
72176 2013-04-06 03:29:34 7.58
72177 2013-04-06 03:30:34 7.58
72178 2013-04-06 03:31:34 7.54
72179 2013-04-06 03:32:34 7.58
72180 2013-04-06 03:33:34 7.58
72181 2013-04-06 03:34:34 7.58
72182 2013-04-06 03:35:34 7.54
72183 2013-04-06 03:36:34 7.58
72184 2013-04-06 03:37:34 7.54
72185 2013-04-06 03:38:34 7.58
72186 2013-04-06 03:39:34 7.58
表温度1(仅提取,此表非常大,有超过 130,000 个值)
ID time temperature
133312 2013-04-06 03:29:36 25.37
133313 2013-04-06 03:30:36 25.37
133314 2013-04-06 03:31:36 25.37
133315 2013-04-06 03:32:36 25.31
133316 2013-04-06 03:33:36 25.31
133317 2013-04-06 03:34:36 25.31
133318 2013-04-06 03:35:36 25.37
133319 2013-04-06 03:36:36 25.31
133320 2013-04-06 03:37:36 25.31
133321 2013-04-06 03:38:36 25.31
133322 2013-04-06 03:39:36 25.37
表格实体(仅提取,此表格非常大,包含超过 130,000 个值)
ID time solids
123791 2013-04-06 03:29:49 140
123792 2013-04-06 03:30:49 140
123793 2013-04-06 03:31:49 143
123794 2013-04-06 03:32:49 140
123795 2013-04-06 03:33:49 140
123796 2013-04-06 03:34:49 140
123797 2013-04-06 03:35:49 140
123798 2013-04-06 03:36:49 143
123799 2013-04-06 03:37:49 140
123800 2013-04-06 03:38:49 140
123801 2013-04-06 03:39:49 140
我目前正在使用下面的查询获取每小时平均值
SELECT DATE_FORMAT(x.time,'%Y-%m-%d %H:00:00')
, avg(x.solids) avg_solids
FROM solids x where time >= NOW() - INTERVAL 1 DAY
GROUP
BY DATE_FORMAT(x.time,'%Y-%m-%d %H:00:00');
如何有效地加入(相对于时间)上面查询的结果,每个传感器 (x3) 显示在 1 个表中
=================================
下面的这个查询获取每小时的值,但不确定如何调整它以获得每小时的平均值
SELECT DATE_FORMAT(timeTable.minuteTime, '%Y-%m-%d %k:%i') time,
(oT2.temperature) temperature,
(T2.temperature) temp,
(S2.solids) solids,
(P2.Ph) Ph
FROM
(
SELECT minuteTime.minuteTime minuteTime,
( SELECT MAX(time) FROM outside_temperature WHERE time <= minuteTime.minuteTime AND time >= NOW() - INTERVAL 1 DAY) otempTime,
( SELECT MAX(time) FROM temperature1 WHERE time <= minuteTime.minuteTime AND time >= NOW() - INTERVAL 1 DAY) tempTime,
( SELECT MAX(time) FROM Ph WHERE time <= minuteTime.minuteTime AND time >= NOW() - INTERVAL 1 DAY) phTime,
( SELECT MAX(time) FROM solids WHERE time <= minuteTime.minuteTime AND time >= NOW() - INTERVAL 1 DAY) solidsTime
FROM
(
SELECT DATE(time) + INTERVAL (HOUR(time) DIV 1 *1 ) HOUR minuteTime
FROM Ph
WHERE time >= NOW() - INTERVAL 1 DAY AND time <= NOW()
UNION SELECT DATE(time) + INTERVAL (HOUR(time) DIV 1 *1) HOUR
FROM solids
WHERE time >= NOW() - INTERVAL 1 DAY AND time <= NOW()
UNION SELECT DATE(time) + INTERVAL (HOUR(time) DIV 1 *1) HOUR
FROM outside_temperature
WHERE time >= NOW() - INTERVAL 1 DAY AND time <= NOW()
UNION SELECT DATE(time) + INTERVAL (HOUR(time) DIV 1 *1) HOUR
FROM temperature1
WHERE time >= NOW() - INTERVAL 1 DAY AND time <= NOW()
GROUP BY 1
) minuteTime
) timeTable
LEFT JOIN outside_temperature oT2 ON oT2.time = timeTable.otempTime
LEFT JOIN temperature1 T2 ON T2.time = timeTable.tempTime
LEFT JOIN solids S2 ON S2.time = timeTable.solidsTime
LEFT JOIN Ph P2 ON P2.time = timeTable.phTime
GROUP BY DATE_FORMAT(timeTable.minuteTime, '%Y-%m-%d %k:%i')
ORDER BY minuteTime ASC
【问题讨论】:
-
没有必要为分组做 date_format 的东西。
GROUP BY DATE(x.time)将完成同样的事情,而无需强制 mysql 进行一堆重复的字符串格式化,无论如何都会被丢弃。 -
您需要每小时或每天(或两者)的平均值吗?还是您需要每小时平均数,然后每天平均每小时平均数?
-
我只需要每小时的平均值,但只需要在表格上显示 1 天的平均值
-
标记,按日期分组(x.time)没有得到所有~24个结果,我只得到2个结果。这可能是由于值之间的第二次延迟!
-
考虑提供 DDL(或 SQLFIDDLE)以及所需的结果集。