需要帮助尝试根据用户输入计算平均值。 C答案

【问题标题】：Need help trying to calculate averages based on user input. C需要帮助尝试根据用户输入计算平均值。 C
【发布时间】：2014-09-23 18:07:40
【问题描述】：

int main() {
int miles_ran, i;
float miles_ran_time, avg_time, sum;

//ask's user for how many miles they ran
printf("How many miles did you run?\n");
scanf("%d", &miles_ran);

//ask's the user for each time that it took them to run each mile
//loop continues asking for each of their time depending on the number inputed above
for (i = 1; i <= miles_ran; i++){
    printf("\nHow long did it take you to run mile #%d\n", i);
    scanf("%d", &miles_ran_time);
}

printf("\nYour average time to run a mile is %.3f.\n", avg_time);

return 0;
}

在尝试获取用户输入的每个不同时间的平均值时，我需要帮助。我似乎无法弄清楚如何去做。例如，如果用户输入他们跑了 3 英里，而这 3 英里的时间分别是 10、10.5 和 9；平均值将达到 9.83。

【问题讨论】：

标签： c average

【解决方案1】：

简单地总结你读到的所有时间并除以总里程数：

sum = 0;

for (i = 1; i <= miles_ran; i++){
    printf("\nHow long did it take you to run mile #%d\n", i);
    scanf("%d", &miles_ran_time);
    sum += miles_ran_time;
}

avg_time = sum / miles_ran;

【讨论】：

【解决方案2】：

做你自己的功课！

您的 9.83 是如何提出的？您将所有数字加在一起并除以英里数，因此在代码中执行相同的操作。在循环中保持一个运行总和 (sum += miles_ran_time;) 然后计算 avg_time。

【讨论】：

【解决方案3】：

您需要将时间相加并除以英里数。

 #include <stdio.h>
    int main() {
        int miles_ran, i;
        float miles_ran_time, avg_time, sum;
        float time  = 0;

        //ask's user for how many miles they ran
        printf("How many miles did you run?\n");
        scanf("%d", &miles_ran);

        //ask's the user for each time that it took them to run each mile
        //loop continues asking for each of their time depending on the number inputed above
        for (i = 1; i <= miles_ran; i++){
            printf("\nHow long did it take you to run mile #%d\n", i);
            scanf("%f", &miles_ran_time);
            time += miles_ran_time;
        }

        printf("\nYour average time to run a mile is %.3f.\n", time/miles_ran);

        return 0;
    }

【讨论】：

【解决方案4】：

一些基本错误。请参阅下面的内联 cmets。

#include <stdio.h>

int main() {
int miles_ran=0, i=0;      /* initialize your variables */
int c;
float miles_ran_time=0.0, avg_time=0.0, sum=0;

//ask's user for how many miles they ran
printf("How many miles did you run?\n");
scanf("%d", &miles_ran);
do { c=getchar(); } while ( c != '\n' && c != EOF );        /* flush input buffer after scanf */

//ask's the user for each time that it took them to run each mile
//loop continues asking for each of their time depending on the number inputed above
for (i = 1; i <= miles_ran; i++){
    printf("\nHow long did it take you to run mile #%d\n", i);
    scanf("%f", &miles_ran_time);                       
    do { c=getchar(); } while ( c != '\n' && c != EOF );    /* flush input buffer after scanf */
    sum += miles_ran_time;                                  /* compute 'sum' from miles ran time */
}

avg_time = sum / miles_ran;                                 /* compute average */

printf("\nYour average time to run a mile is %.3f.\n", avg_time);

return 0;
}

输出：

$ ./bin/avg
How many miles did you run?
5

How long did it take you to run mile #1
10.1

How long did it take you to run mile #2
9

How long did it take you to run mile #3
9.5

How long did it take you to run mile #4
9.8

How long did it take you to run mile #5
9.7

Your average time to run a mile is 9.620.

【讨论】：