从 1000 行文本中查找总工资和平均工资

Question

我需要编写一个 python 程序来读取 1000 行文本，并计算每个教授类别（助理、副教授、全职、所有教员）的总工资和平均工资。问题来了：

一所大学将其员工工资发布在 http://cs.armstrong.edu/liang/data/Salary.txt。文件中的每一行 由教师的名字、姓氏、职级和薪水组成（见 练习 13.16）。编写程序显示总工资 助理教授、副教授、正教授等 教师，分别显示助理的平均工资 教授、副教授、正教授和所有教职员工， 分别。

这是我目前的代码：

import urllib.request

def main():
    infile = urllib.request.urlopen('http://cs.armstrong.edu/liang/data/Salary.txt')
    s = infile.read().decode().splitlines()

    asstTotal = 0
    asstCount = 0
    asscTotal = 0
    asscCount = 0
    fullTotal = 0
    fullCount = 0

    for line in s:
        if "assistant" in line:
            asstCount += 1
            asstTotal += int(float(s[3]))

        if "associate" in line:
            asscCount += 1
            asscTotal += int(float(s[3]))

        if "full" in line:
            fullCount += 1
            fullTotal += int(float(s[3]))

    allFacTotal = asstTotal + asscTotal + fullTotal
    avgAsst = int(asstTotal / asstCount)
    avgAssc = int(asscTotal / asscCount)
    avgFull = int(fullTotal / fullCount)
    avgAll = int(allFacTotal / 1000)

    print("Total assistant professor salary is", asstTotal)
    print("Total associate professor salary is", asscTotal)
    print("Total full professor salary is", fullTotal)
    print("Total faculty salary is", allFacTotal)
    print("Average assistant professor salary is", avgAsst)
    print("Average associate professor salary is", avgAssc)
    print("Average full professor salary is", avgFull)
    print("Average faculty salary is", avgAll)

main()

我不知道如何从各自的教授级别中获取薪水，并对它们进行总计和平均。任何意见将不胜感激！

结果：

Total assistant professor salary is 24306418
Total associate professor salary is 27235856
Total full professor salary is 27631726
Total faculty salary is 79174000
Average assistant professor salary is 79174
Average associate professor salary is 79174
Average full professor salary is 79174
Average faculty salary is 79174

Answer 1

这可以用来解释任何类型的排名，方法是在字典中为每个职位建立一个薪酬列表，然后简单地将总和除以长度。

我的例子：

import urllib.request

def main():
    infile = urllib.request.urlopen('http://cs.armstrong.edu/liang/data/Salary.txt')
    s = infile.read().decode().splitlines()

    pays = {}

    for line in s:
        *name, rank, pay = line.split()
        pays[rank] = pays.get(rank, []) + [float(pay)]

    for rank, sals in pays.items():
        avg = sum(sals) / len(sals)
        print("{:>10} ({:3}): ${:,.2f}".format(rank.title(), len(sals), avg))


if __name__ == '__main__':
    main()

还有输出：

Associate (344): $83,849.26
     Full (349): $102,229.37
Assistant (307): $65,949.55

Answer 2

import urllib.request

def main():
    infile = urllib.request.urlopen("http://cs.armstrong.edu/liang/data/Salary.txt")

    asstSalTotal = 0
    asstTotal = 0
    asscSalTotal = 0
    asscTotal = 0
    fullSalTotal = 0
    fullTotal = 0

    for line in infile.readlines():
        data = line.decode().split()
        designation = data[2]
        if designation == "assistant":
            asstSalTotal += float(data[3])
            asstTotal += 1
        elif designation == "associate":
            asscSalTotal += float(data[3])
            asscTotal += 1
        elif designation == "full":
            fullSalTotal += float(data[3])
            fullTotal += 1

    allSalTotal = asstSalTotal + asscSalTotal + fullSalTotal
    allTotal = asstTotal + asscTotal + fullTotal

    print("Total Salary:\n\tAssistant:\t%d\n\tAssociate:\t%d\n\tFull:\t%d\n\tAll:\t%d\n\nAvg Salary:\n\tAssistant:\t%d\n\tAssociate:\t%d\n\tFull:\t%d\n\tAll:\t%d\n" % (asstSalTotal, asscSalTotal, fullSalTotal, allSalTotal, asstTotal, asscTotal, fullTotal, allTotal))


main()

Answer 3

在 python2.7 中，使用urllib2.urlopen 并将工资按标题与表格组合在一起。

在python3中，使用urllib.request.urlopen并将print ..改为print(..)

import urllib2

rs = urllib2.urlopen('http://cs.armstrong.edu/liang/data/Salary.txt')
title_salaries = {}

for line in rs.read().split("\n"):
    _, _, title, salary = line.split(' ')
    if not title_salaries.has_key(title):
        title_salaries[title] = []

    title_salaries[title].append(float(salary))

for title, salaries in title_salaries.items():
    print title
    print 'avg:', sum(salaries) / len(salaries)
    print 'total:', sum(salaries)
    print