【发布时间】:2018-12-06 03:40:25
【问题描述】:
我有这个对象:
{
"apple": {
"0": {
"2018-04-25 19:51:38": {
"x": "38.0",
"y": "23.0"
},
"2018-04-25 19:51:39": {
"x": "NaN",
"y": "NaN"
},
"2018-04-25 19:51:40": {
"x": "NaN",
"y": "NaN"
}
},
"5": {
"2018-04-25 19:51:38": {
"x": "50.0",
"y": "35.0"
},
"2018-04-25 19:51:43": {
"x": "21.0",
"y": "3.0"
}
},
"6": {
"2018-04-25 19:51:34": {
"x": "30.0",
"y": "15.0"
},
"2018-04-25 19:51:39": {
"x": "NaN",
"y": "NaN"
},
"2018-04-25 19:52:40": {
"x": "22.0",
"y": "20.0"
},
"2018-04-25 19:52:42": {
"x": "33.0",
"y": "45.0"
}
}
},
"team": {
"2": {
"2018-04-25 19:51:35": {
"x": "32.0",
"y": "25.0"
},
"2018-04-25 19:51:36": {
"x": "33.0",
"y": "40.0"
},
"2018-04-25 19:51:37": {
"x": "12.0",
"y": "24.0"
},
"2018-04-25 19:51:38": {
"x": "33.0",
"y": "45.0"
}
},
"3": {
"2018-04-25 19:51:35": {
"x": "2.0",
"y": "3.0"
},
"2018-04-25 19:51:36": {
"x": "4.0",
"y": "5.0"
},
"2018-04-25 19:51:37": {
"x": "12.0",
"y": "15.0"
},
"2018-04-25 19:51:38": {
"x": "33.0",
"y": "45.0"
}
},
"4": {
"2018-04-25 19:51:35": {
"x": "20.0",
"y": "30.0"
},
"2018-04-25 19:51:36": {
"x": "41.0",
"y": "35.0"
},
"2018-04-25 19:51:37": {
"x": "32.0",
"y": "65.0"
},
"2018-04-25 19:51:38": {
"x": "43.0",
"y": "49.0"
}
},
"5": {
"2018-04-25 19:51:35": {
"x": "21.0",
"y": "33.0"
},
"2018-04-25 19:51:36": {
"x": "31.0",
"y": "12.0"
},
"2018-04-25 19:51:37": {
"x": "34.0",
"y": "54.0"
},
"2018-04-25 19:51:38": {
"x": "93.0",
"y": "22.0"
}
}
}
}
我想要的是两个唯一时间戳数组:一个用于apple,一个用于team。
所以:
const appleTimestamps = ["2018-04-25 19:51:34", "2018-04-25 19:51:37", "2018-04-25 19:51:38", "2018-04-25 19:51:39", "2018-04-25 19:51:40", "2018-04-25 19:51:43", "2018-04-25 19:52:40", "2018-04-25 19:52:42"]
const teamTimestamps = ["2018-04-25 19:51:35", "2018-04-25 19:51:36", "2018-04-25 19:51:37", "2018-04-25 19:51:38"]
如您所见,Apple 和团队内部的密钥不是连续的。
我怎样才能做到这一点?我认为唯一的方法是使用find,但我确定我错了。
(我也可以使用 Lodash)
【问题讨论】:
标签: javascript object unique lodash