【发布时间】:2015-04-02 10:32:48
【问题描述】:
我正在处理消息系统,我需要从每个向登录用户发送消息的用户那里获取最后一条消息。我在 mongoDB 中有这个结构:
[{
"_id": "551bd621bb5895e4109bc3ce",
"from": "admin",
"to": "user1",
"message": "message1",
"created": "2015-04-01T11:27:29.671Z"
}, {
"_id": "551bd9acf26208ac1d9b831d",
"from": "user1",
"to": "admin",
"message": "message2",
"created": "2015-04-01T11:42:36.936Z"
}, {
"_id": "551bdd6d849d53001dd8a64a",
"from": "user1",
"to": "user2",
"message": "message3",
"created": "2015-04-01T11:58:37.858Z"
}, {
"_id": "551bdd99849d53001dd8a64b",
"from": "user2",
"to": "admin",
"__v": 0,
"message": "message4",
"created": "2015-04-01T11:59:21.005Z"
}, {
"_id": "551bdda1849d53001dd8a64c",
"from": "user1",
"to": "admin",
"__v": 0,
"message": "message5",
"created": "2015-04-01T11:59:29.971Z"
}]
我需要从向登录用户发送消息的每个用户的最后一条消息中获取字段 from、message 和 created。我尝试使用 distinct,但它只返回一个字段。我有这个:
Message.find({
to: req.user.username
})
.select('message created')
.sort('-created')
.exec(function (err, messages) {
if (err) {
return res.status(400).send({
message: getErrorMessage(err)
});
} else {
res.json(messages)
}
});
但它会返回所有向登录用户发送消息的用户,我只需要拥有唯一用户和他们的最后一条消息。有没有办法用猫鼬做到这一点?
【问题讨论】:
标签: node.js mongodb mongoose unique